BS - Mid-term 1-25 - Mid-term 1 formula PDF

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Mid-term 1 formula...

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Mid-term 1-25

MGMT 1009: Business Statistic Mid-term part 1

1

Probability with greater than A populationhas a mean of 400 and a standard deviation of 25. A sample of 100 observations will be taken. The probability that the sample meanwill be larger than 405 is

n/N ≤ 0.05 P (z ≥ max.z)

Infinite population

Ex = μ

400 25 100

𝜎 n σ =

σ n

2.50

max. z (+) max

405 5.00

max. z = (+)/σ

2.00

P (z ≥ max.z) z in right hand side

#DIV/0!

0.00 #DIV/0!

Max z

#DIV/0!

0.00

0.00

#DIV/0!

#DIV/0!

Std Normal distribution = 1 - Std norm 0.9772 0.0228 #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0!

1

2.00 #DIV/0! #DIV/0! #DIV/0!

2

#DIV/0!

Min. Std norm

1 1 1 1

Scatter

Dependent variable y

Independent Variable x 1 2 3 4 5

Dependent variable y 5 4 3 2 1

6 5 4 3 2 1 0 0

1

2

3

4

5

22 Independent Variable x 1 2 3 4 5 10

Dependent variable y 5 4 3 2 1 -4

Chart Title 6 5 4 3 2 1 0 -1 0

2

4

6

8

10

-2 -3 -4 -5

4

x? A professor at a local university noted that the exam grades of her students wer normally distributed witha mean of 73 and a standard deviation of 11. If 69.5 percent of the students received grades of C or better, what is the minimum score of those who received C's x? P(z ≥ x-μ/σ)

Z table

5

a b c

μ = mean σ = Std.Dev P(z) P(x-μ/σ) = 1 - P(z)

73.00 11.00 69.5% 0.3050

1.0000

1.0000

z = x-μ/σ x

-0.510 67.39

#NUM! #NUM!

#NUM! #NUM!

Probability no more than Probability of having sales of no more than $60,000 i Daily Sales (In $1,000s) $ 40.00 $ 50.00 $ 60.00 $ 70.00 Sum f(x) = a+b+c

Probability f(x) 0.1 0.4 0.3 0.2 0.8

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6

Mid-term 1-25

10

Regresion analysis Regression analysis was applied between sales (in $1000s) and advertising (in $100s), and the - Brainly.co Regression analysis was applied between sales (in $1,000s) and advertising (in $100s and the following regression function was obtainedŷ = 500 + 4x and the following regression function was obtainedŷ = 80 + 6.2x Based on the above estimated regression line, if advertising is $10,000, then the point estimate for sales (in dollars) is __

ads

sales

15

given x advertising advertising x value

$ $ $

10,000.00 100.00 100.00

#DIV/0!

#DIV/0!

y= sales ŷ = 80 + 6.2x y sales value

$ $ $

1,000.00 700.00 700,000.00

#DIV/0! #DIV/0!

#DIV/0! #DIV/0!

A regression analysis between sales(in $1000) and price (in dollars) resulted in the following equatio ŷ = 50000 - 8x Question 14 A regression analysis between sales (Yin $1,000) and advertising (X in dollars) resulted in... - HomeworkL

y (x+1) = 50,00 - 8(x+1) y (x+1) = 50,00 - 8x - 8 = y(x) - 8

given x price y(x) - 8 y= sales y sales value

11

$ $ $ $

1.00 -8.00 1,000.00 -8,000.00

$

-

$

-

Probability P between w/o n The starting salaries of individuals with an MBA degree are normally distributed with mean of $40.000 and a standard deviation of $5,000 What percentage of MBA'swill have starting salaries of $34.000 to $46,000?

16

The time it takes to travel from home to the office is normally distributed with μ= 25 minutes and σ= 5 minut What is theprobability the trip takes between 20 and 30 minute?

μ Standard deviation 𝜎 x1 x2

𝑧 =

𝑧 =

$ $ $ $

11 40,000.00 5,000.00 34,000.00 46,000.00

16 25 5 20 30

-1.2

-1

𝑥 − 𝜇 𝛿 𝑥 − 𝜇 𝛿

P(z...