Central Net Force Worksheet Answers PDF

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Central Net Force Worksheet Answers...

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gmName Date

Pd

Cent r alNetFor cePar t i cl eModel :

Revi ew Sheet d

a

f c e

b

1.Att het opoft hefir s th i l lo ft her ol l e r c oa s t e r ,p oi nt“ a , ”a6 0k gpa s s e n g e rf e e l sa si fs he“ we i gh s ”50 0 N.Exp l a i nwhi c hf or c epr o v i d e st h es e n s a t i o no fwe i g h t .Ho wf a s ti st her o l l e r c o a s t e rg o i n go v e rt he3 mr a d i ush i l l t o pt oc r e a t et h i ss e n s a t i o n ?Dr a waq u a n t i t a t i v ef o r c ed i a gr a mf o rt h es i t u a t i o n. FN = 500N

N )  600N Fg mg  60kg (10 kg

(Fg  FN )r mv 2  v2  r m (600N  500N )3.0 m 2 5.0 ms2  v  2.2 ms v2  60 kg Fnet  Fg  FN 

Fg = 600N

2 .Atp o i n t“ b ”t h er o l l e r c o a s t e rh a sr e a c h e das p e e do f2 8m/ s .Ho wl a r g emu s tt h er a d i uso ft h ev a l l e yb e s ot h a ta1 00k gr i d e rwi l le x p e r i e n c ean o r ma lf or c eo ffiv et i me st he i rwe i g h t( 5G’ s ) ? Dr a waq u a n t i t a t i v ef or c ed i a gr a mf o rt h es i t u a t i o n . FN = 5000N

Fg mg  100kg (10 Nkg ) 1000N Fnet  FN  Fg 

mv 2 mv 2 100kg(28 ms) 2  r  r 20 m r ( FN  Fg ) (5000 N  1000 N)

Fg = 1000N

3 .Atp o i n t“ c ”a7 0k gr i d e ri st r a v e l i n ga t2 0m/ si na7 me t e rr a di u sc u r v e . Dr a waq u a n t i t a t i v ef or c ed i a gr a mf o rt h er i d e r . FN = 4000N

N  Fg mg  70kg (10 kg ) 700N

Hor : Fnet

FN 

mv 2 70kg(20 ms ) 2  FN   4000N r 7.0m

Fg = 700N

4 .Atp o i n t“ d ”a4 0k gc h i l di su p s i de d o wna tt h et o po ft h el o o p. Ho wf a s two u l dt h et r a i nh a v et op a s s t h r o u g ht h e4me t e rr a di u sc u r v et op r o d u c ea2 0 0Nd o wn wa r dn o r ma lf o r c eo nt h ec h i l d ? Dr a waq u a n t i t a t i v ef or c ed i a gr a mf o rt h ec h i l d .

©Modeling Instruction – AMTA 2013

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U7 Central Force Model - Review v3.1

N Fg mg  40kg (10 kg )  400N

Fnet  FN  Fg  400N  200 N  600 N

FN = 200N

2

600 N 

(600N )r (600 N)4.0m mv 2  v2    60 ms2  v  7.7 ms 40kg r m

Fg = 400N

5 .Ex i t i n gt h el oo pa tv a l l e y“ e ”t h e20 0 0k gr o l l e r c oa s t e re x e r t sad o wn wa r dn o r ma lf o r c eo nt het r a c ko f 9 0 , 0 0 0N. Th et r a c kr a d i u si s1 3 0me t e r s .Dr a waq u a n t i t a t i v ef o r c ed i a g r a mf o rt h er o l l e r c oa s t e rt r a i n . 90,000N

Fg = 20,000N 6 .Att h et o po fh i l l“ f ”t h er o l l e r c o a s t e rc r e s t st h e5 me t e rr a d i u sc u r v ea t6m/ s .Dr a waq u a n t i t a t i v e f o r c ed i a gr a mf ora6 0k gp a s s e n g e r . Ho wma n yG’ swo u l da n yp a s s e n g e rf e e la tt h et o po ft h eh i l l ? FN = 170N

N  Fg mg  60kg (10 kg ) 600N

mv 2 mv 2 60 kg(6.0 ms ) 2  FN  Fg   FN  600N  Fnet  Fg  FN  r r 5.0 m 170 N .28 G' s FN 600 N  432 N 170 N G's  600 N

Fg = 600N

7 .Ac a rt r a v e l so v e rah i l la tc o n s t a n ts p e e d .I ft h er a d i uso ft h eh i l li s3 0me t e r s ,a twh a ts p e e dwo u l d t h ec e n t r i p e t a lf o r c ee q u a lt h ef o r c eo fg r a v i t y ?I ft h ec a rwe r et oe x c e e dt h i ss p e e d ,wh a two u l d h a p p e nt ot hec a r ?

mv 2 mv 2 Fnet  Fg  FN   Fg  0  r r 2 mv N  v  gr  10 kg (30m) mg  r v 17 ms

FN = 0

v

r

Fg =

If the car exceeds this speed it will lose contact with the hill.

©Modeling Instruction – AMTA 2013

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U7 Central Force Model - Review v3.1

8 .He r ei st h ed a t af o rt h es p a c es h u t t l ei ni t so r b i ta r o u nde a r t h : Sh u t t l ema s si no r b i t=9 4 , 8 0 2k g ma s so ft h ee a r t h=6x1 024k g s h u t t l eo r b i t a lh e i g h ta b o v et hee a r t h=2 . 7 6x1 05m r a d i u so ft h ee a r t h=6 . 3 8x 1 06m s h u t t l et a n g e nt i a lv e l o c i t ywh e ni no r b i t=7 8 2 3m/ s e c a .Us et h ep r i n c i p l e so fc i r c u l a rmo t i o nt ofin dt h ec e nt r i p e t a lf or c e n e c e s s a r yt ok e e pt h es h u t t l ei n i t sc i r c u l a ro r bi ta r o un de a r t h .

94,802 kg(7823 ms ) 2 mv 2  Fc  6.38 10 6 m  .276 10 6 m r 94,802kg (7823 ms )2  870,000N Fc 6.66 10 6 m Fnet Fg 

b .Us eNe wt o n ’ sLa wo fUn i v e r s a lGr a v i t a t i ont ofin dt h egr a v i t a t i o na lf o r c e t hee a r t he x e r t so nt h e s h u t t l ewh e nt h es hu t t l ei si no r b i t . Fg G

mearthm ss  6.67 10 11 2 r

Nm2 2 kg

(6.0 1024 kg )94,802kg 860,000N (6.66 106 m)2

c .Ho wd ot h ev a l u e sc a l c u l a t e di np a r t saa n dbc o mp a r et oo n ea n o t h e r ?Ex p l a i n . Th e yd i ffe rb ya b o u t1 %.Th e ys ho u l db et h es a me .Iwo u l dg u e s si ti sd u et or ou n d i n gwh e n v a l u e swe r ep r o vi d e d .

©Modeling Instruction – AMTA 2013

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U7 Central Force Model - Review v3.1...