Title | Chemistry 1 Consider the species: F2+, F2, and F2–. Which of these species will be paramagnetic? |
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Author | Kolbaev Matraimov |
Course | Polymer Chemistry |
Institution | University of South Florida |
Pages | 1 |
File Size | 86.9 KB |
File Type | |
Total Downloads | 100 |
Total Views | 170 |
Consider the species: F2+, F2, and F2–. Which of these species will be paramagnetic? According to molecular orbital (MO) theory, the twelve outermost electrons in the O2molecule are distributed as follows:...
Week 13 Practices with Answers
For Questions 1-3 use the following Molecular Orbital diagram: 1. Consider the species: F2+, F2, and F2–. Which of these species will be paramagnetic? A) Only F2 B) F2+ and F2 – C) F2 and F2 D) F2+ and F2– 2. According to molecular orbital (MO) theory, the twelve outermost electrons in the O2 molecule are distributed as follows: A) 12 in bonding MOs, 0 in antibonding MOs B) 10 in bonding MOs, 2 in antibonding MOs C) 9 in bonding MOs, 3 in antibonding MOs D) 8 in bonding MOs, 4 in antibonding MOs E) 7 in bonding MOs, 5 in antibonding MOs 3. According to molecular orbital theory, what is the bond order in the O2+ ion? A) 5.5 B) 5 C) 4
Answers: 1D, 2D, 3D
D) 2.5
E) 1.5...