Collision Cart Lab-Simulation Version 2 PDF

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Collision Cart Lab Physics

Name ____________________________

https://www.physicsclassroom.com/Physics-Interactives/Momentum-and-Collisions/CollisionCarts/Collision-Carts-Interactive Perform the following collisions and record your results: Before

After Stopped

Slow

???

???

Elastic (Bounce)

Change in Momentum /Kinetic Energy v = 0 m/s

v = 3 m/s

v = 1.5 m/s

v = 4.5 m/s

∆ P=P f −P i Momentum (P) = mass x velocity Red Cart mred = 3 kg

Blue Cart mblue = 1 kg

kgm s ∆ Ke=Kef − Kei ΔKered = 3.375-13.5 = -10.125 J

ΔPblue = 4.5-0 = 4.5

Kered initial = 0.5*3*3^2 = 13.5 J Kered final= 0.5*3*1.5^2 = 3.375 J Keblue initial = 0.5*1*0^2= 0 J Keblue final = 0.5*1*4.5^2 = 10.125 J

kgm s ΔKe

PTotal initial = 9+0 = 9 Total

ΔPred = 4.5-9 = -4.5

kgm Pred initial = 3*3 = 9 s kgm Pred final= 3*1.5 = 4.5 s kgm Pblue initial = 0*1 = 0 s kgm Pblue final = 4.5*1 = 4.5 s

kgm s

KeTotal initial = 13.5+0 = 13.5 J

PTotal final = 4.5+ 4.5 = 9

kgm s

KeTotal initial = 3.375+10.125= 13.5

J

1. What was the change in momentum of the red cart? -4.5

kgm s

2. What was the change in momentum of the blue cart? 4.5

kgm s

blue = 10.125-0 = 10.125J

ΔP Total = 9-9 =0

kgm s ΔKe Total = 13.5 – 13.5 =0 J

3. Was momentum conserved in this collision? How do you know? Yes because before and after the collision there is still the same amount of momentum meaning none was lost and all was conserved. 4. What was the change in Kinetic energy of the red cart? -10.125

J

5. What was the change in Kinetic energy of the blue cart? 10.125

J

6. Was Kinetic energy conserved in this collision? How do you know? Yes because before and after the collision there is still the same amount of kinetic energy meaning none was lost and all was conserved and the change is zero.

Before

After

Slow

Fast

???

???

Elastic (Bounce)

Change in Momentum /Kinetic Energy v = 3 m/s

v = -7 m/s

v = -12 m/s

v = -2 m/s

∆ P=P f −P i Momentum (P) = mass x velocity Red Cart mred = 1 kg

Blue Cart mblue = 3 kg

kgm s ∆ Ke=Kef − Kei ΔKered = 72-4.5= 67.5 J

ΔPblue = -6--21=15

Kered initial = 0.5*1*3^2= 4.5 J Kered final= 0.5*1*-12^2 = 72 J Keblue initial = 0.5*3*-7^2= 73.5 J Keblue final = 0.5*3*-2^2= 6 J

kgm s ΔKe

PTotal initial =3+-21= -18 Total

ΔPred = -12-3= -15

kgm Pred initial = 1*3= 3 s kgm Pred final= 1*-12= -12 s kgm Pblue initial = 3*-7= -21 s kgm Pblue final = 3*-2= -6 s

kgm s

KeTotal initial = 4.5+73.5=78 J

= 6-73.5= -67.5 J

blue

ΔPTotal = -15+15= 0

kgm PTotal final = -12+-6 = -18 s KeTotal final = 72+6 = 78 J

7. What was the change in momentum of the red cart? -15

kgm s

8. What was the change in momentum of the blue cart? 15

kgm s

kgm s ΔKe Total = 67.667.5= 0 J

9. Was momentum conserved in this collision? How do you know? Yes because before and after the collision there is still the same amount of momentum meaning none was lost and all was conserved. 10. What was the change in Kinetic energy of the red cart? 67.5 11. What was the change in Kinetic energy of the blue cart? -67.5

J J

12. Was Kinetic energy conserved in this collision? How do you know? Yes because before and after the collision there is still the same amount of kinetic energy meaning none was lost and all was conserved and the change is zero.

Before Fast

After Medium

???

???

Inelastic (Stick)

Change in Momentum /Kinetic Energy v = 8 m/s

v = -5 m/s

v = 0.2 m/s

v = 0.2 m/s

∆ P=P f −P i

Momentum (P) = mass x velocity

kgm s ¿ kgm Pred final= 2*0.2= 0.4 s kgm Pblue initial = 3*-5= -15 s kgm Pblue final = 3*0.2= 0.6 s

ΔPred = -15.6

Pred initial = 2*8= 16

Red Cart mred = 2 kg

kgm s ∆ Ke=Kef − Kei ΔKered = -63.96 J

ΔPblue = 15.6

Kered initial = 0.5*2*8^2=64 J Kered final= 0.5*2*0.2^2=0.04 J Keblue initial = 0.5*3*-5^2= 37.5 J Keblue final = 0.5*3*0.2^2=0.06 J

Blue Cart mblue = 3 kg

kgm s ΔKe

PTotal initial = 1 Total

kgm s

KeTotal initial = 101.5 J

kgm s KeTotal final = 0.1 J

PTotal final = 1

13. What was the change in momentum of the red cart? -15.6

kgm s

14. What was the change in momentum of the blue cart? 15.6

kgm s

blue

= -37.44 J

ΔPTotal = 0 ΔKe

Total

kgm s

= -101.4 J

15. Was momentum conserved in this collision? How do you know? Yes because before and after the collision there is still the same amount of momentum meaning none was lost and all was conserved.

16. What was the change in Kinetic energy of the red cart? -63.96 17. What was the change in Kinetic energy of the blue cart? -37.44

J J

18. Was Kinetic energy conserved in this collision? How do you know? No because the total change in kinetic energy is not equal to zero meaning some was lost and converted to heat or sound energy.

Before

After Fast

Stopped

???

???

Inelastic (Stick)

Change in Momentum /Kinetic Energy v = 0 m/s

v = -3 m/s

kgm Pred initial = 0 s kgm Pred final= 2*-3= -6 s kgm Pblue initial = 1*-9= -9 s kgm Pblue final = 1*-3 = -3 s

Red Cart mred = 2 kg

Kered initial = 0 J Kered final= 0.5*2*-3^2=9 J Keblue initial = 0.5*1*-9^2= 40.5 J Keblue final = 0.5*1*-3^2= 4.5 J

Blue Cart mblue = 1 kg

PTotal initial = -9 Total

v = -9 m/s v = -3 m/s Momentum (P) = mass x velocity

kgm s

KeTotal initial = 40.5 J

19. What was the change in momentum of the red cart? -6

kgm s KeTotal initial = 13.5 J

∆ P=P f −P i ΔPred = -6

kgm s

∆ Ke=Kef − Kei ΔKered = 9 J

ΔPblue = 6

ΔKe

kgm s

blue

= -36 J

ΔPTotal = 0

kgm s

PTotal final = -9

kgm s

20. What was the change in momentum of the blue cart? 6

kgm s

21. Was momentum conserved in this collision? How do you know? Yes because before and after the collision there is still the same amount of momentum meaning none was lost and all was conserved. 22. What was the change in Kinetic energy of the red cart? 9

J

23. What was the change in Kinetic energy of the blue cart? -36

J

24. Was Kinetic energy conserved in this collision? How do you know? No because the total change in kinetic energy is -26 which is not equal to zero meaning some was lost and converted to heat or sound energy.

25. What was the change in momentum of the red cart? -10

kgm s

26. What was the change in momentum of the blue cart? 10

kgm s

27. Was momentum conserved in this explosion? How do you know? Yes because before and after the collision there is still the same amount of momentum meaning none was lost and all was conserved. 28. What was the change in Kinetic energy of the red cart? 30 29. What was the change in Kinetic energy of the blue cart? 45

J J

30. Was Kinetic energy conserved in this collision? How do you know? No because the total change in kinetic energy is not equal to zero meaning some was lost and converted to heat or sound energy.

31. What was the change in momentum of the red cart? -10

kgm s

32. What was the change in momentum of the blue cart? 10

kgm s

33. Was momentum conserved in this explosion? How do you know? Yes because before and after the collision there is still the same amount of momentum meaning none was lost and all was conserved. 34. What was the change in Kinetic energy of the red cart? -5

J

35. What was the change in Kinetic energy of the blue cart? 46.03

J

36. Was Kinetic energy conserved in this collision? How do you know? No because the total change in kinetic energy is not equal to zero meaning some was lost and converted to heat or sound energy....