Examen problemas mayo PDF

Title Examen problemas mayo
Course Análisis de circuitos
Institution Universidad de Alcalá
Pages 3
File Size 407.7 KB
File Type PDF
Total Downloads 117
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Summary

❆♣ ❡❧❧✐❞♦s✿ ◆♦♠❜r❡✿ ❉✳◆✳■✳✿ ●r✉♣ ♦●r❛♥❞❡✿ ❊s❝✉❡❧❛P♦❧✐té❝♥✐❝❛❙✉♣ ❡r✐♦r ❉❡♣❛rt❛♠❡♥t♦❞❡❚❡♦rí❛❞❡❧❛❙❡ñ❛❧②❈♦♠✉♥✐❝❛❝✐♦♥❡s ●r❛❞♦s❚■❈ ❆s✐❣♥❛t✉r❛✿❆♥á❧✐s✐s❞❡❈✐r❝✉✐t♦s✲P✳❊✳■✳✸ ❈✉rs♦✿✶♦✳ ❯◆■❱❊❘❙■❉❆❉❉❊❆▲❈❆▲➪ ❋❡❝❤❛✿✶✺✕♠❛②♦✕✷✵✶✾■♥str✉❝❝✐♦♥❡s❘❡❧❧❡♥❡ t♦ ❞♦s ❧♦s ❞❛t♦s q✉❡ s❡ ♣✐❞❡♥ ❡♥ ❡st❛ ♣á❣✐♥❛✳▲❛♣r✉❡❜❛❝♦♥st❛❞❡✷♣r♦❜❧...


Description

H(s) = L C

V (s) Eg (s)

RL

C

+ eg(t)

L

Rg

Rg = 50 Ω;

1 Q=√ ; 2

RL · H(s) = Rg + RL

v(t)

1 l´ım |H(ω)| = ; ω→∞ 2

RL

1 ω0 = √ Krad/s 2

s2   RL 1 Rg RL 1 2 · + s + · + RL C Rg + RL LC Rg + RL L

L = 50 mH C = 20 µF RL = 50 Ω

ω = 103 rad/s eg (t), Rg

v(t) a:1 eg(t) L2

L1

C

RL

v(t)

Rg

Perfecto

H(s) =

V (s) Eg(s)

L1 C v(t) eg (t) = 21 ·

(ωt) ; Rg = 225 Ω; RL = 25 Ω; L2 = 250µH

a s Rg C  H(s) = 2 1 a 1 1 s2 + + s+ RL Rg C L2 C C = 4 mF L1 = 2,25 mH B = 20 rad/s Q = 50 a = 3 v(t) = 1,5776 ·

ω = 1020 rad/s

(1020t − 1,1032) V...


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