Hardy Weinberg Problems T FB PDF

Preview

Summary

Download Hardy Weinberg Problems T FB PDF

Description

AP Biology

Mr. Brown

Hardy-Weinberg Problems Directions – On a separate piece of paper, solve the following problems using the Hardy-Weinberg equilibrium principle. Be certain to show all work and to explain all reasoning.

1. In guinea pigs, black coat color (B) is dominant to albino (b). In a population of guinea pigs, 16% are white. Determine the frequency of both alleles and each genotype in the population. 2. In cattle, black coat color is dominant to red coat. In a herd of 1000 cattle, 750 have black coats. Determine the frequency of both alleles and each genotype in the population. 3. If an isolated population has the following gene frequency: g = 0.8, what percent of the population will be homozygous dominant (GG), homozygous recessive (gg) and heterozygous (Gg)? 4. In Andalusian fowl, the gene for black plumage is incompletely dominant to the gene for white plumage. The resulting heterozygous individuals have slate blue plumage. In a flock of 1000 fowl, 90 have black plumage. Determine the frequency of each allele and each genotype in the population. 5. A population of 200 organisms consists of 100 members of each sex. Both sexes initially exhibit the same genotypic frequencies: 25% AA; 50% Aa; 25% aa. For some reason, males with the homozygous recessive genotype are incapable of mating. Determine the genotypic frequencies of all members of the next generation.

Hardy-Weinberg Problems Answers 1. In guinea pigs, black coat color (B) is dominant to albino (b). In a population of guinea pigs, 16% are white. Determine the frequency of both alleles and each genotype in the population. q2 = 0.16 [bb] q = 0.4 [b] p = 0.6 [B] p2 = 0.36 [BB] 2pq = 0.48 [Bb] 2. In cattle, black coat color is dominant to red coat. In a herd of 1000 cattle, 750 have black coats. Determine the frequency of both alleles and each genotype in the population. 250/1000 = 0.25 = q2

q = 0.5 [r] p2 = 0.25 [RR]

p = 0.5 [R] 2pq = 0.50 [Rr]

3. If an isolated population has the following gene frequency: g = 0.8, what percent of the population will be homozygous dominant (GG), homozygous recessive (gg) and heterozygous (Gg)? p = 0.2 [G] q2 = 0.64 [Gg]

q = 0.8 [g] 2pq = 0.32 [Gg]

p2 = 0.04 [GG]

4. In Andalusian fowl, the gene for black plumage is incompletely dominant to the gene for white plumage. The resulting heterozygous individuals have slate blue plumage. In a flock of 1000 fowl, 90 have black plumage. Determine the frequency of each allele and each genotype in the population. 90/1000 = 0.09 = p2 [BB]

p = 0.3 [B] q2 = 0.49 [Bb]

q = 0.7 [b] 2pq = 0.42 [Bb]

5. A population of 200 organisms consists of 100 members of each sex. Both sexes initially exhibit the same genotypic frequencies: 25% AA; 50% Aa; 25% aa. For some reason, males with the homozygous recessive genotype are incapable of mating. Determine the genotypic frequencies of all members of the next generation. Total = 200 organisms ♀:

25% AA 50% Aa 25% aa

  

Freq. = ♂:

25% AA 50% Aa Freq. =

50 A 0a 50 A 50 a 0 A 50 a 100 A 100 a 0.5 [A] 0.5 [a]

50 A 0a 50 A 50 a 100 A 50 a 0.67 [A]0.33 [a]

 

F2 generation: 1/2 A 1/2 a

2/3 A 2/3 AA 2/3 Aa

2/3 AA :

1/2 Aa :

1/3 a 1/6 Aa 1/6 aa

1/6 aa...