Hardy weinberg questions PDF

Preview

Summary

Questions and answers on Hardy Weinberg equilibrium. Dr.Emma Test taken online on April 2018...

Description

1.True or false? The Hardy–Weinberg model makes the following assumptions: no selection at the gene in question; no genetic drift; no gene flow; no mutation; random mating. True False

2.What is the frequency of the A1A2 genotype in a population composed of 20 A1A1 individuals, 80 A1A2 individuals, and 100 A2A2 individuals? 0.1 80 0.4 0.5 3.Cystic fibrosis is a genetic disorder in homozygous recessives that causes premature death in many individuals. If 9 in 10,000 newborn babies have the disease, what are the expected frequencies of the dominant (A1) and recessive (A2) alleles according to the Hardy-Weinberg model? A1 = 0.9604, A2 = 0.0392 A1 = 0.9997, A2 = 0.0003 A1 = 0.9600, A2 = 0.0400 A1 = 0.9800, A2 = 0.0200 A1 = 0.9700, A2 = 0.0300 4.What genotype frequencies are expected under Hardy–Weinberg equilibrium for a population with allele frequencies of p = 0.8 and q = 0.2 for a particular gene? The expected genotype frequencies are 0.64, 0.32, and 0.04 for A1A1, A1A2, and A2A2, respectively. (Why: the expected frequency of the A1A1 genotype is p^2=(0.8)(0.8)=0.64; the expected frequency of the A1A2 genotype is 2pq=2(0.8)(0.2)=0.32; the expected frequency of the A2A2 genotype is q^2=(0.2)(0.2)=0.4. To verify your calculations, confirm that the three frequencies add up to one. 5.Which of the following evolutionary forces could create new genetic information in a population? Mutation Selection Non-random mating Genetic drift

If a population is NOT in Hardy-Weinberg equilibrium for a specific gene, which statement is the most accurate? Natural selection is acting on this gene. Individuals with one form of the gene have greater mating success. At least one of the Hardy-Weinberg assumptions has been broken. New forms of the gene have entered the population due to immigration.

What is the frequency of the A1 allele in a population composed of 20 A1A1 individuals, 80 A1A2 individuals, and 100 A2A2 individuals? The frequency of the A1 allele is 0.4 The frequency of the A1 allele is 0.5 The frequency of the A1 allele is 0.7 The frequency of the A1 allele is 0.1 The frequency of the A1 allele is 0.3

Which of the following statements is not a part of the Hardy–Weinberg principle? When alleles are transmitted to the next generation according to the rules of Mendelian inheritance, their frequencies do not change over time. All of the statements are true. If allele frequencies in a population are given by p and q, then genotype frequencies will be given by p2, 2pq, and q2 for generation after generation. Even if allele A1 is dominant to allele A2, it does not increase in frequency. The genotype frequencies in the offspring generation must add up to two.

Which of the following evolutionary forces consistently results in adaptive changes in allele frequencies? Mutation Selection Inbreeding

There is no evolutionary force that results in adaptive changes in allele frequencies. A hypothetical population of 200 cats has two alleles, TL and TS, for a locus that codes for tail length. The table below describes the phenotypes of cats with each possible genotype, as well as the number of individuals in the population with each genotype. Which statements about the population are true? Select all statements which are true.

Genotype

TL TL

TL TS

TS TS

Phenotype (tail length)

Number of individuals in population

long 60

medium 40

short 100 Heterozygotes make up 20% of the population. Assuming random mating, each gamete has a 40% chance of having a TL allele and a 60% chance of having a TS allele. The number of heterozygotes are the same as you would expect if this population was in Hardy Weinberg equilibrium. Homozygotes make up 80% of the population. In the entire cat population, the frequency of the TS allele is 0.4. In the entire cat population, 60% of the alleles are T S. Homozygotes make up 30% of the population. There are less heterozygotes than would be expected if this population was in Hardy Weinberg equilibrium. Assuming random mating, each gamete has a 50% chance of having a TL allele and a 50% chance of having a TS allele. In the entire cat population, the frequency of the TS allele is 0.5. There are more heterozygotes than would be expected if this population was in Hardy Weinberg equilibrium....