Isotopes and Atomic Mass Lab Report chem2 PDF

Title Isotopes and Atomic Mass Lab Report chem2
Author Yousra Kay
Course Chemistry For Consumers: Chemistry And Crime
Institution Middle Tennessee State University
Pages 2
File Size 45.7 KB
File Type PDF
Total Downloads 80
Total Views 151

Summary

good report have to do the calculations on your own because they might be different but here is some examples for it...


Description

1

Isotopes and Atomic Mass Lab Report Questions 1: binding energy is the energy required to hold the nucleus together To calculate the binding energy; E=mc2 M= the difference in mass in(kg), between what’s measured and what’s expected by adding up the component’s protons and neutrons. C= the speed of light squared Mass defect = predicted mass – observed mass M= 6.6978*10^-27 – 6.646*10^-27 = 5.18*10^-29Kg Convert from Kg to J E=m*c^2

5.18*10^-29 * (3*10^8)2

5.18*10^-29 * 9*10^16 = 4.662*10^-12J

Question 3: By a system called beta decay, C decays. An atom of 14C decays into an atom of 14N during this process, during which one of the neutrons in the carbon atom becomes a proton. This raises the number of protons in the molecule by five, forming a nitrogen atom instead of a carbon atom.

Question 4: 215x present at 25% and 217x presents at 75% 215*25/100 + 217* 75/100 = 215*0.25 +217*0.75 =53.75+162.75 =216.5 amu.

Question 5: average mass of chlorine listed in the periodic table: 35.453

kanakrieh 2 Number of chlorine-35 atoms:10 Number of chlorine-37 atoms:3 Weighted average calculated in simulation: 35.43amu Question 6: Number of chlorine-35 atoms:10 Number of chlorine-37 atoms:3 Weighted average calculated in stimulation: Question 7: 0.7577*34.969 + 0.2423*36.996= 35.453amu

Questions8: mg-24=23.9850 Mg-25=24.9858 Mg-26=25.9826 23.9850+24.9858+25.9826/3=24.984amu...


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