Title | Lab 2 - Capacitors Worksheet X-1 |
---|---|
Author | Jagga Daku |
Course | Physics II Lab |
Institution | Arizona State University |
Pages | 4 |
File Size | 128.8 KB |
File Type | |
Total Downloads | 76 |
Total Views | 138 |
Download Lab 2 - Capacitors Worksheet X-1 PDF
PHY132 – LAB 2: CAPACITORS – WORKSHEET Data (40):
Name:
Analysis and Answering Lab Qs(40):
Partners:
TOTAL (80):
TA: 1) Parallel Plate Capacitor: Add Screenshots
a. A = 200 mm2 = ……….….m2;
d = 5.0 mm = ……………m.
κ (dielectric constant )=1(air ) C=
ϵ0 A 1 2 =¿ ……………. (Unit); Q=C ×V = ……………. (Unit); E= C V = …………… 2 d
(Unit). (Calculated)
C=¿……………. (pF); Q=¿……………. (Unit); E=¿ …………… (Unit). (Measured in the simulation) Do the measured values agree with the calculated ones? b. A’ (~doubled) = …………. m2;
d = 5.0 mm = ……………m.
κ (dielectric constant )=1(air ) ' ' ' C =¿……………. (pF); Q =¿ ……………. (Unit); E =¿ …………… (Unit). (Measured
in the simulation) How do the primed values differ from the initial measured values in step a? c. A = 200 mm2 =
m2; d’ (~doubled) = ……………m.
' ' ' C =¿……………. (pF); Q =¿ ……………. (Unit); E =¿ …………… (Unit). (Measured
in the simulation) How do the primed values differ from the initial measured values in step a? d. A = 200 mm2 = …………. m2;
κ (dielectric constant )=3.5 (paper ) 1
d = 5.0 mm = …………m.
' ' ' C =¿……………. (pF); Q =¿ ……………. (Unit); E =¿ …………… (Unit). (Measured
in the simulation) How do the primed values differ from the initial measured values in step a? e. Add your comments/ a conclusion – answer questions in the manual for these parts.
f. Calculating the dielectric constant κ for the paper. A = 200 mm2 = ……….….m2; −12
ϵ 0=8.85× 10
Δ x (mm)
d = 5.0 mm = ……………m.
κ ac (paper =3.5)
F /m
0
2
4
6
8
10
12
14
C (pF) P = pico = 10^-12 -0.05952 Slope - m = ……………….. (unit)
κ m = ……………………
(show work) y-intercept - b = ……………….. (unit) ……………………….
κ b=
(show work)
κ ave =
κ m+ κ b = ………………………; 2
………………………. Screenshot of the Logger Pro plot
2
% error with κ ac =
PART II. Capacitors in parallel – sharing charges Capacitors in Parallel:
V 0=9 Volts ,C 1=0.1 F , C 2 =0.2 F
a- Charging C1: Q 1 =C 1∗V 0= …………….. (pC) ;
V 1 ( measured )=¿…………………..(Volt)
b- Sharing the charge stored on C1 with capacitor C2
V2Meas. (measured across C1 or C2) = …………… (Volt);
Q 1 New =C 1∗V 2 Meas .= ……………(pC) ;
Q net =Q 1 New+Q 2=¿ …………………(pC). How close this value to Q 1from part a?
Q 2 =C 2∗V 2 Meas .= ……….. (pC)
why?
V 2 Theo. =
Q1 = ………… (V). How close this value to the measured value of C1 +C 2
V2 ? % diff between V 2 Theo . And V 2 Meas . = ………………..%
PART III. Finding an unknown equivalent capacitance of capacitors connected in series
V0 = 9 Volts, 0.2 F. 3
C1 = 0.1 F,
C2 = 0.05 F,
C3 = 0.1 F,
C4 =
a- Charging C1: Q 1=C 1∗V 0= …………….. (pC) ;
V 1 ( measured ) =¿…………………..(Volt)
b- Finding the unknown equivalent capacitance of C2, C3 and C4 Voltage Across each capacitor (Volt) V1New (for step 2) = V2 = V3 = V4 =
Charge on each capacitor Q i = Ci* Vi. (Coulomb) Q1New (for step 2) = Q2 = Q3 = Q4 = Q234 = (this is a conclusion)
What is your note about the charge on each one of the C2, C3 and C4 capacitors?
V234 = V2+ V3+ V4 = …………………. Volt. How close this value to V1New from? why? Do the charge on each capacitor differ from the others? What is Q234 = ……………?
Qtot = Q1New + Q234 = ………………………(C); How close this value to Q 1from part a? why?
Vtot = V1New = V234 = …………………….(V); why?
C tot =
Q tot V tot
=……………………….(F);
C234 = …………………………….. (use the fact that C tot =C1 +C 234 ), why?
C 234 ( accepted )=¿ ………………………. (Use equation (7) in the manual).
% error of C 234 =¿……………………………………… %
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