Module Two One Dimensional Kinematics Distanceand Displacement PDF

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One Dimensional Kinematics Distance vs Displacement Practice Problems 1. A person travels from their home to the store that is 2.50km away. When he gets back home, what is his A. Distance traveled? 5km because he had to go two ways and 2.5+2.5=5 Since the distance to the store was 2.5km and the distance would be the same, the total distance would be 5km B. Displacement? 0 because he returned to his original point When he returns home, there is no displacement because that is the original point

2. What is the displacement of a moving object that follows the equation x(t)=3.5t2+8t-15

a. From t=0.0s to t=5.0s? t=0

t=5

d=-15

d=112.5

I plugged in 0 for t and I got -15 for the displacement which means it started at -15 units I plugged in 5 for t and I got 112.5 for the displacement

If I use the equation to find the total displacement, I get 127.5 units The displacement of this moving object is 127.5 units I got this because I found how much the position of this moving object changed during this elapsed time. b. From t=3.5s to t=8.3s? t=3.5s

t=8.3s

d=55.875

d=292.515

I plugged in 3.5 for t and got 55.875 I plugged in 8.3 for t and got 292.515 If I use the equation for the displacement during this time period, I get 236.64 units The displacement of this object is 236.64 units I got this because this was the displacement of the moving object during the elapsed time.

3. A man observes people walking along a beach. One person in particular is measured walking back and forth in a straight line and is seen at the positions indicated in the chart below. The time recorded is the time from one point to the next.

Position

Position (m)

Time (s)

A

0.0

0

B

8.5

14

C

-3.2

7

D

-9.4

11

A. What is the total distance traveled from A to D?

The total distance is 9.4 m The original position is 0 and with distance, there is no direction so position D is 9.4 m away from position A

B. What is the total displacement from A to D? The total displacement is 0-9.4= -9.4 m Displacement has a direction and since position D was 9.4 m away from A in a negative direction, the displacement would be -9.4 meters

C. If the man went from D straight back to B, what is the total distance traveled? The total distance would be 9.4+8.5= 17.9 meters Regardless of the direction, that’s how far away they are from each other.

D. If the man went from D straight back to B, what is the total distance traveled? This question was probably trying to ask for the displacement

If he was going from point D to point B, he would be travelling in a positive direction so it would be 9.4+8.5=17.9 meters...