Title | MTM TEST 3 12 - test |
---|---|
Author | Monica Elias |
Course | Mathematics 2 |
Institution | Namibia University of Science and Technology |
Pages | 2 |
File Size | 147.9 KB |
File Type | |
Total Downloads | 69 |
Total Views | 153 |
test...
POLYTECHNIC OF NAMIBIA
http://www.polytechnic.edu.na
SCHOOL OF HEALTH AND APPLIED SCIENCES Private Bag 13388, Windhoek, Namibia Phone: +264 (61) 207 2780 +264 (61) 207 2142
Fax:
DEPARTMENT OF MATHEMATICS & STATISTICS
Programme
Bachelor of Engineering
Course
Engineering Mathematics 125
Course Code
MTM210S
Level
6
Date
18 October 2012
Duration
1 Hour and 30 minutes
Total Marks
51
Examiners
Mr. F N NDINODIVA
Moderator
Mr. B OBABUEKI
CONTINUOUS ASSESSMENT TEST 3 (1st opportunity)
Instructions/Information to candidates: 1. 2. 3. 4. 5.
Examination conditions apply at all times. NO books, notes or cell phones allowed. No borrowing or lending of any equipment or stationery. Use of a non-programmable pocket calculator is required. Answer all questions and number your solutions correctly. Only blue or black ink may be used for written work. Work in pencil will not be marked.
6. Correction fluid (Tippex) may not be used. 7. Untidy / illegible work will attract no marks. 8. Round all answers to three (3) decimal places, unless indicated otherwise in a question.
Question 1 [16 marks] 1.1
Analyze the nature of each of these ordinary differential equations
1.1 .1 ( y ' 4xy )2 2 ye x 1.1 .2 k (ut ) 7 1.2
2 u 2 u x 2 y 2
Form a differential equation from the family of functions y Ae4 x e6 x
[4] [4]
[8]
Question 2 [20 marks] 2.1
Use the separable variable method to solve the following initial value problem to obtain a particular solution for p dp 1 p p (1 ) , where a and L are constants and the initial value condition dt a L p(0) p0 ;0 p0 L [15]
2.2
By using a special case of variable separation equation leading to homogeneous dy [5] (homogeneous solutions), solve ( x2 xy) x2 y y2 . dx
Question 3 [15] Use any suitable method to solve each of the following differential equations 3.1 3.2
cos x
dy y sin x cos2 x dx
ex sin ydx (2 y ex cos y) dy 0
[6] [9]...