Perhitungan Struktur Balok Beton Lengkap Excel.xlsx XLSX

Title	Perhitungan Struktur Balok Beton Lengkap Excel.xlsx
Author	Isandre Fajarrachman
File Size	8 MB
File Type	XLSX
Total Downloads	387
Total Views	468

Summary

Isandre Fajarrachman S.T, MSi. Rasio Tu Data luas Spefikasi tul. Tumpuan 787.665 atas D.tump atas = 13 mm 240.577 bawah n.atas = 2 D.tump bawah = 13 mm n.bawah = 2 Spefikasi tul. Lapangan D.lap atas = 19 mm n.atas = 2 s D.lap bawah = 16 mm n.bawah = 3 Spefikasi tul. Geser D.sengkang = 10 mm Perhitun...

Description

Isandre Fajarrachman S.T, MSi. Rasio T Data luas Spefikasi tul. Tumpuan 787.665 atas D.tump atas = 13 mm 240.577 bawah n.atas = 2 D.tump bawah = 13 mm n.bawah = 2 Spefikasi tul. Lapangan D.lap atas = 19 mm n.atas = 2 s D.lap bawah = 16 mm = 3 Spefikasi tul. Geser D.sengkang = 10 mm Perhitungan Rasio Tulangan Atas Input Data Nilai Satuan Ket. Input = 57.25 Kn/m momen ultimit Input Mn = 63.611 Kn/m momen nominal Input Rn = 6.867 koefisien tahanan Input p = 0.02113 rasio tulangan Input p.min = 0.00340 rasio tul.minimum p.min-2 = 0.00357 rasio tul.minimum-2 p.maks = 0.024 rasio tul.maks-2 Cek p Input p > ok 0.00340 p.min p > ok 0.00357 p.min-2 p < ok 0.024 p.maks maka diambil nilai p Perhitungan As Data Nilai Satuan Ket. As = 787.665 mm2 luas tul.lentur As-min = 126.670 mm2 luas tul.lentur minimum As-min-2 = 133.037 mm2 luas tul.lentur minimum-2 Cek As As > ok 787.67 As min As > ok 126.67 As min-2 maka diambil nilai AS Jumlah Tulangan terpasang Data Nilai Satuan Ket. n.bawah Mu (input) Rumus : Pengecekan rasio tulangan momen. Mn = Mu/φlentur Rn = /( . ^2 ) p = (0.85 ^ ) / ) p.min = ( /(4.. p.min-2 = 1.4. / p.maks = 0,75.((0,85. ^ p > p.min p< p.maks As = p.b.d As min = ( /(4.. As min2 = 1.4. / .b.d As > As.min p = As/b.d SNI Beton 2847-2013 - Pasal 10.5. Tulangan minim lentur...