Title | Spss week 11 - Lecture notes 1 |
---|---|
Author | Farzan Kamoosi |
Course | Statistics |
Institution | Macquarie University |
Pages | 2 |
File Size | 92.1 KB |
File Type | |
Total Downloads | 35 |
Total Views | 124 |
hello bye i dont have any good notes bye...
MKTG2002 | Week 11 Activity
Individual task: Data analysis 2 (bivariate analysis-test of differences) Preparation: (1) Download the three data files at the Week 11 section on iLearn, (2) upload the data files together (drag them together to the Temporary Files) to your SPSS via AppStream, (3) open each data file (Click “File” > Click “Open” > Click “Data” > Select the data file from Temporary Files). (1) Independent samples t-test 1. Open the data file “Independent samples t-test data” in your SPSS. The data file is available at the Week 11 section on iLearn. 2. Your tutor will demonstrate how to test “whether the anxiety test scores differ between children from divorced parents and other children.” 3. Read Part 1 in the instruction file “Week 11 SPSS guide”. 4. Your task: test “whether the depression test scores differ between children from divorced parents and other children” and report the results in one sentence (the same style as the template).
Mean = 15.67 for not divorsed and 7.5 for divorsed Sig value is < 0.05 therefore we use significant variances not assumes -
P- value is 0.052 – we accept the null hypothesis T - 52 = -1.993 Therefore, there is no significant difference in depression between children from divorced parents and other children.
(2) Paired samples t-test 1. Open the data file “Paired samples t-test data” in your SPSS. 2. Your tutor will demonstrate how to test “whether the 3 exams are equally difficult for students.” 3. Read Part 2 in the instruction file “Week 11 SPSS guide”. 4. Your task: test “whether students’ weights are the same before and after the physical training” and report the results in one sentence (the same style as the template).
There is no difference between the means of students weight before, there is a difference between the means of students weight. P value = 0.001 therefore we reject the null hypothesis as p-value...