Title | 3.4 Assessment for Grading Unit 3 Curve Sketching |
---|---|
Course | Calculus and Vector |
Institution | Carleton University |
Pages | 29 |
File Size | 1.5 MB |
File Type | |
Total Downloads | 13 |
Total Views | 52 |
1.a.b.2.a.The domain of the function isThe function is neitherc.The function is odd a. The vertical asymptotes are x = 7 and x = - b.The vertical asymptotes are x = -1 ; x = -3 and x = 2 a. Since the polynomial in the numerator is a bigger deghorizontal asymptote. ree than the denominator, there is ...
1. a.
b.
2. a.
The domain of the function
is
b.
The domain of the function
is
c.
The domain of the function
is
3. a.
The function b.
is even
The function
is neither
c.
The function
is odd
4. a.
The vertical asymptotes are x = 7 and x = -4 b.
The vertical asymptotes are x = -1 ; x = -3 and x = 2
5. a.
Since the polynomial in the numerator is a bigger degree than the denominator, there is no horizontal asymptote.
b.
Since the polynomial in the numerator is a lower degree than the denominator, y = 0 is the horizontal asymptote.
c.
Since the numerator and denominator have the same degree
The horizontal asymptote is y = 2
6. a. i)
The critical value is
ii) The intervals
Intervals
2x + 3
4(2x+3)
Increasing or decreasing
-
-
Decreasing
+
+
Increasing
The function
is increasing on the interval
The function
is decreasing on the interval
iii)
Since the function changes from decreasing to increasing at the value
minimum point at
b. i)
. The minimum point is
, there is a
.
The critical values are 2 and 4
ii) Intervals
Intervals
x-2
x-4
3(x - 2)(x - 4)
Increasing or decreasing
x 1
The function
is concave down on the intervals -1 < x < 1
Points of inflection
Since the function changes from concave down to concave up at x = -1, there could be an inflection point at = −1 . However, = −1 is a restriction on the domain. There is no point of inflection at x = -1. Since the function changes from concave up to concave down at x = 1, there could be an inflection point at = 1 . However, = 1 is a restriction on the domain. There is no point of inflection at x = 1. Therefore, there is no point of reflection Sketch the curve...