AP Chemistry Unit 4 Kinetics Study Guide PDF

Title AP Chemistry Unit 4 Kinetics Study Guide
Author Sam Zamat
Course AP Chemistry
Institution Fairfield Ludlowe High School
Pages 12
File Size 449 KB
File Type PDF
Total Downloads 87
Total Views 192

Summary

This is a comprehensive study guide for AP Chemistry's unit on Kinetics. In this class, we call it unit four, but I believe it is unit 5 according to the AP Chem CED....


Description

Collision Theory ● Collision Theory states that in order to react, molecules must collide ● Bonds are being broken and reformed in a ratio, and atoms are exchanged/moved around ● Not all collisions result in a reaction because they must meet the two general criteria ○ If requirements are not met, no reaction will occur or even take place ● Every reaction has a different/unique threshold of activation energy ○ Lower 𝐸𝑎 = Faster reaction because there are more successful collisions ○ Higher 𝐸𝑎 = Slower reaction because there are many low energy collisions Requirements for Collision Requirement

Qualitative Reasoning

Sufcient Activation Energy (𝐸𝑎)

The molecules must collide hard enough because to break bonds requires a large amount of energy

Proper Orientation

Molecules need to break and make bonds in order for a chemical reaction to occur, therefore, the alignment and position of the molecules is vital given that molecules bond in specic contexts

Rate and Factors that Affect It ● The rate of a reaction is the speed at which a chemical process occurs ● Physical State of the Reactants (solid, liquid, gas, aqueous) ○ The more contact between reactants, the more collisions that will occur ■ We want to increase collisions and increase the energy of collisions ○ Gas mixtures and solutions react faster than solids and liquids (movement!) ■ It is preferable to make a solid/liquid into a gas for experimental data ○ Solids will react faster when in smaller pieces ● Concentration of Reactants (Molarity (M)) ○ Higher concentration of reactants will result in more collisions ● Temperature ○ Faster moving molecules collide more frequently and with greater force ■ At higher temperatures, high-energy collisions happen more frequently ● Presence of a Catalyst ○ Catalysts speed up reactions by changing the mechanism (steps) of the reaction ○ Catalysts are not consumed during the course of the reaction ○ Example: Catalysts can gather reactants and place them in the proper orientation with enough energy in order to collide with one another successfully Reaction Coordinate Diagrams ● These diagrams can also be called reaction pathway diagrams or energy diagrams

● Activation Energy ( 𝐸 ): The minimum amount of energy required to initiate a reaction 𝑎

○ The reaction will not occur until it overcomes the 𝐸𝑎 (successful collisions) ○ Smaller Eₐ results in faster reactions and a smaller hill on the diagram ○ Larger 𝐸𝑎 results in slower reactions and a larger hill on the diagram ○ 𝐸𝑎 = 𝐸𝑇𝑟𝑎𝑛𝑠𝑖𝑡𝑖𝑜𝑛 𝑆𝑡𝑎𝑡𝑒 - 𝐸𝑅𝑒𝑎𝑐𝑡𝑎𝑛𝑡𝑠 ● Change in Energy (∆𝐸): The difference in energy between reactants and products ○ The ∆𝐸 can be either positive or negative ○ ∆𝐸 = 𝐸𝑃𝑟𝑜𝑑𝑢𝑐𝑡𝑠 - 𝐸𝑅𝑒𝑎𝑐𝑡𝑎𝑛𝑡𝑠 ● Transition State/Activated Complex: Seen at the peak of the reaction coordinate diagram ○ It is at a low concentration and is very unstable because it may form a product, or it may fall back to the reactant state of matter ● Change: ∆ = Final - Initial ● Exothermic: Energy is released/given off during the reaction - Negative ∆𝐸 (exit) ● Endothermic: Energy is absorbed during the reaction - Positive ∆𝐸 (enter) ● Intermediate: A usually stable step of a reaction between the reactant and the product ○ When there is an intermediate, it is essentially multiple reactions in one ○ When a reaction has an intermediate, there are more transition states ○ We can determine which step of intermediate diagrams are faster (hill height) ○ We can determine overall exo v. endo between intermediates Types of Reaction Coordinate Diagrams Single-Step

Multistep

Boltzmann Distribution Curves ● Area under the curve represents all molecules in a reaction and their speed ● A particular activation energy is required for the reaction – shown by the vertical line

○ All collisions of this particular speed and above will have enough energy to react ○ The molecules with a speed to right of vertical line will have proper 𝐸𝑎 ○ Catalysts can shift the vertical line to the left, allowing more molecules to collide ● Higher temps lead to more molecules meeting energy required for a successful collision ○ Curves with higher temperatures will be more shifted to the right of the graph ● Approximate average represented by µ = ((𝑟𝑜𝑜𝑡)(𝑚𝑒𝑎𝑛))

2

Catalysts ● Catalysts increase the rate of reaction by decreasing the activation energy ● Catalysts change the mechanism(s) by which the process occurs ● A lower 𝐸𝑎 would lead to a higher speed/rate ○ More molecules can get over the 𝐸𝑎 threshold, allowing more successful collisions ● Catalyzed reactions are often studied in terms of reaction coordinate diagrams

Reaction Rates ● Rates of reactions can be determined by monitoring the change in concentration of a reactant or a product over time

○ Units: Molarity per second (M/s) - Square brackets around a compound is molarity ■ Example: [NO] ○ Remember: Molarity = mol/L ● We can watch the decrease of reactants or increase of products to analyze rates ○ Reactants are high in M at the beginning of a reaction, and then decrease ○ Products are low in M at the beginning of a reaction, and then increase ● In a reaction, the amount of moles does not change, so we can predict amounts ○ Conservation of Mass - Makes sense because if R turns to P, we haven't lost or gained any additional matter from the beginning Instantaneous versus Average Rates ● Instantaneous Rates: One moment in time of a reaction ● Average Rates: The rate of a reaction over a period of time ● The “rate” always refers to instantaneous, unless otherwise indicated Average Rate ● Average Rate (M/s): The change in concentration divided by the change in time ○ Equation: Average Rate =

∆𝑀 ∆𝑇

● As the reaction advances, the average rate always decreases/slows down ○ Concept Check: This is because there are less reactants to react - lower probability Instantaneous Rate ● Instantaneous Rate: The rate of reaction at a specic time (not average) ● Graphs are used to plot the concentration versus the time ○ Instantaneous rate represented by slope of a line tangent to the curve at any point ● All reactions slow down over time - compare the steepness of the two slopes ○ The steeper the slope of the instantaneous rate, the faster the rate of change ● The best indicator of the “rate” of a reaction is the instantaneous rate near the beginning, when there are the most reactants ○ This is called the initial rate, which is a type of instantaneous rate ■ Initial rates are always positive

Reaction Rate and Stoichiometry ● The rate of reactant appearance

disappearance = rate of product

● Mole ratios can be created from diagrams in order to write balanced chemical equations ● We can also use reactions to nd rates of change of other reactants and/or products

Rate Laws ● One way to examine how the [reactants] affect the rate of reaction is to do many experiments, vary the [reactant] one at a time, and measure the rate. 𝑥

𝑦

● Rate Law Statement: Rate = k[𝐴] [𝐵] ○ The rate constant (k) changes with temperature and is different for every reaction ■ Temperature dependent ○ Only the reactants are included in the rate law statement ○ Exponents are the rate order - Not same as the coefcients from the equation ○ To nd the rate constant, plug in numbers and solve for k ■ Equation Units of k:

1 𝑡𝑥𝑀

𝑂𝑣𝑒𝑟𝑎𝑙𝑙 𝑂𝑟𝑑𝑒𝑟 − 1

● Overall rate orders are found by adding up all of the orders of each reactant Table Logic ● Compare two experiments where one reactant changes and other stays constant ○ Analyze how the initial rate responds ● We can write rate laws based off of the orders found from the table

Handy Log Rule ● Used for one reactant at a time and the other reactant must be held constant

● Useful when the numbers are not easily manipulated and/or hard to estimate ○ Equation: Order =

𝑙𝑜𝑔 (𝑟𝑎𝑡𝑒 𝑟𝑎𝑡𝑖𝑜) 𝑙𝑜𝑔 (𝑐𝑜𝑛𝑐𝑒𝑛𝑡𝑟𝑎𝑡𝑖𝑜𝑛 𝑟𝑎𝑡𝑖𝑜)

○ Make sure that the ratios come from the same row in the table and match Finding Rates with No Constants ● When given a table or information with no constant reactant, we have a way to nd ra ● Before using the equation, use table logic to nd the order of the obvious reactant ● Equation:

𝑟𝑎𝑡𝑒 1 𝑟𝑎𝑡𝑒 2

=

𝐴 𝑥 𝐵 𝑦 𝐵 𝐴

( )( )

○ After nding the order of one of the obvious reactants, simplify 𝑥

○ Once in the simplied form it should look something like this: 1 = 0. 5 ○ Either guess and check for either 0, 1, or 2 by plugging in or use logBAE ■ logBAE: Click MATH button on calculator and go to logBASE ● 𝑙𝑜𝑔(𝑏𝑎𝑠𝑒)

(𝑎𝑛𝑠𝑤𝑒𝑟)

= exponent (order)

Differential Rate Laws Summary ● Chemists cannot look at the stoichiometry of a chemical equation and know its rate law ● Rate laws MUST be determined experimentally ● Rate laws can be determined by observing the effect on rate when changing initial concentrations - How the speed of a reaction varies with concentration ● The orders are usually 0, 1, or 2, but they can be higher, fractional, or even negative ● How the speed of a reaction varies with the concentrations of the reactants, using differential rate laws. Differential versus Integrated Rate Laws ● Use the differential rate law when the data is given in concentrations and rates ● Use the integrated rate law when the darta is given in concentrations and time (not rates) ○ The equations are used to study only individual reactants Integrated Rate Law: 1st Order Equation: ln [𝐴]𝑡- ln [𝐴]0= -kt ○ Subscripts are treated as indicators and are not factored into equation Solve for any one of the four variables in equation when given the other three ○ Determine the concentration of some reactant remaining at any time after the reaction proceeds for some time ○ Calculate the time required for a reactant to drop to a particular level Graphing 1st Order Integrated Rate Laws ○ If the reaction is 1st order, plotting ln[A] vs time yields a linear graph ○ The slope tells you k (rate constants can NEVER be negative)

■ The slope will be negative ○ The y intercept is ln [𝐴]0(initial concentration) ○ 1st order reactions always have a constant half-life ○ The x-axis will be time and the y-axis will be ln concentration

Integrated Rate Law: 2nd Order ● Equation:

1 [𝐴]

𝑡

1 [𝐴]

= kt 0

○ Subscripts are treated as indicators and are not factored into equation ● Paralleled with the equation for a straight line: y = mx + b ● Graphing 2nd Order Integrated Rate Laws ○ Plotting

1 [𝐴]

vs time will give a linear graph 𝑡

○ The slope tells you k (rate constants can NEVER be negative) ■ The slope will be positive ○ The y-intercept =

1 [𝐴]

(initial concentration) 0

○ The x-axis will be time and the y-axis will be

Integrated Rate Law: 0th Order

1 [𝐴]

0

● Equation: [𝐴]𝑡- [𝐴]0= -kt ○ Subscripts are treated as indicators and are not factored into equation ○ This is the same equation as the rst order without the natural logarithms ● Graphing 0th Order Integrated Rate Laws ○ Plotting [𝐴]𝑡vs time will give a linear graph ○ The slope tells you k (rate constants can NEVER be negative) ■ The slope will be negative ○ The y-intercept = [𝐴]𝑡 ○ The x-axis will be time and the y-axis will be [𝐴]𝑡

Half Life ● Half Life ( 𝑡1/2): Time required for the concentration to drop to half of its previous value ● Half life is a convenient way to describe how fast a reaction occurs ● Fast reactions have a short half life and slow reactions have a long half life ● Equation of Half-Life Only Applicable to 1st Order Reactions: 𝑡1/2=

0.693 𝑘

○ First order reactions always have a constant half life (does not change/vary) ● Determining Half Life from 1st Order Graphs ○ Find the point where the original [A] drops to ½ the starting amount ● Chemists can also plug in half of given concentrations into equations to nd 𝑡 1/2

● Conceptual Remaining Reactant/Product: 100 → 50 → 25 → 12.5 → 6.25 → 3.125 →… ● There IS a difference between the amount of disappearance and the amount remaining Methods to Determine Reaction Order

● Table Logic can be applied to tables with concentrations and rates ● Graphs can be used when concentration and time is given ● Handy Log Rule can be applied to tables with concentrations and rates Methods to Determine Rate Constant (k) ● Identify the slope of linear graph ● Write rate law and plug in Methods to Determine Half-Life ● In 1st Order Reactions: 𝑡1/2=

0.693 𝑘

● Plug in ½ of [𝐴]0 to [𝐴]𝑡 ● Estimate from graph (only applies to molarity vs time) Rate Laws and Half Life Summary 0th Order

1st Order

2nd Order

Rate Law

Rate = k

Rate = k[A]

Rate = k[𝐴]

Integrated Rate Law

[𝐴]𝑡- [𝐴]0= -kt

ln [𝐴]𝑡- ln [𝐴]0= -kt

Plot for Linear Graph Slope Half-Life

[A] vs time -k 𝑡1/2=

ln[A] vs time

2𝑘

0

𝑡1/2=

1 [𝐴]

𝑡

1 [𝐴]

-k [𝐴]

1 [𝐴]

2

= kt 0

vs time 𝑡

k

0.693 𝑘

𝑡1/2=

1 𝑘 [𝐴]

0

Reaction Mechanisms ● Most chemical reactions do not occur in a single step as the balanced equation implies ● Reaction Mechanism: A series of individual steps in which a chemical reaction occurs ○ Elementary Step: Each individual reaction that describes molecular collision/event ○ The rate law of an elementary step can be deduced from the reaction stoichiometry ■ NOT true from overall balances reactions ● The rate law is directly related to how many molecules are involved in an elementary step ○ Unimolecular: 1 reactant (A → product and rate = k[A]) 2

○ Bimolecular: 2 reactants (2A → P (rate = k[𝐴] ) OR A+B → P (rate = k[A][B])) 2

○ Termolecular: 3 reactants (2A + B → P and rate = k[𝐴] [B] ■ Hard to meet requirements, so not likely (Bad proposed mechanism) Reaction Mechanism: Slow 1st Step

● Chemists cannot determine the rate law from the overall balanced reaction ○ Chemists must see a proposed mechanism ● The slow step determines the rate ○ When the slow step is 1st...the rate law includes only the reactants of that 1st step ■ “The team is only as strong as its weakest member” ○ Do not cross anything off to come up with the rate law ○ If only one step is given as a proposed mechanism, assume it is the slow step ● Intermediate: The product in the rst step and the reactant in the second ● Catalyst: Does not get used in reaction and appears on reactant of 1st AND 2nd steps ● Writing Rate Laws + Overall Reactions from Reaction Mechanisms with a Slow 1st Step ○ 1. Circle reactants of the rst step - The rate law only includes these reactants ○ 2. Find orders using stoichiometric relationships (coefcients) ○ 3. Write rate law ○ 4. Determine intermediates and catalysts and cross them out ○ 5. Determine catalysts and cross them out ○ 6. Write what remains in the mechanisms to determine overall reaction ■ Remember to write the number of times the R/P appear in BOTH steps Reaction Mechanism: Slow 2nd Step ● The rate determining mechanism will be the second step because the second is slow ● Intermediate: The product in the rst step and the reactant in the second ● Catalyst: Does not get used in reaction and appears on reactant of 1st AND 2nd steps ● Writing Rate Laws + Overall Reactions from Reaction Mechanisms with a Slow 2nd Step ○ 1. Cross off the intermediates and catalysts ○ 2. Include the reactants up to and including the slow step (do not use last fasts steps) ○ 3. Any products before the slow step (in the fast step) show up in the denominator (shown as a negative exponent) Arrhenius Equation ● Equation: k = Ae

−𝐸

𝑎

𝑅𝑇

○ k = rate constant ○ A = frequency factor – frequency of collisions between molecules ○ 𝐸 = activation energy 𝑎

○ R = 8.314 J/mol-K ○ T = temp in Kelvin ● Know conceptual basis of equation: Puts together the rate constant and collision theory ○ Shows that the rate constant is temperature dependent ● Increasing rate with increasing temp is non-linear - Depends on fraction of molecules with enough energy the number of collisions, and proper orientation

Beer-Lambert Law ● Lab: A way to measure the concentration of a colored solution ○ Visualizing the rate of reaction that only works with a color that changes over time ● Equation: A = ϵ𝑏𝑐 ○ A = Absorbance of the light of the beam being shot through the analyte ■ Units are in AU ○ ϵ = Molar absorptivity (constant based on the chemical/analyte being tested) ○ b = path length (constant based on the side of the container) ○ c = concentration (this is what we are looking for) ■ A or proportional to c, allowing us to use them interchangeably (A/time) ● See which is linear over time to determine the rate of reaction ● Spectrophotometer: A piece of lab equipment used in the lab ○ Allows us to select the complementary color of the analyte to use as a beam ■ This will create a certain type of wavelength specic to the solution ■ This further maximizes the absorption to gather most accurate results ○ Transmittance: How much light comes out of analyte (opposite of absorbance) ■ Low concentration results in low absorbance ■ Low concentration results in high transmittance ● Darker colors have a higher absorbance (black shirt in sunny day) ● Absorbance decreases over time ● Wavelength of the beam is determined by the color - Specic wavelength used in the lab ● A calibration curve is necessary to convert between correct units ● We can take any absorbance from the lab graph and nd corresponding concentration Multiple Choice Tips ● Spend at most 1.5 minutes on each MC and return to it when done with MC if incomplete ● Process of Elimination: Identify the answers you for sure know are incorrect ● Remember that not having a calculator is actually helpful ○ These questions are not intended for extremely difcult calculations ○ Look at the answers to the question and rule out any that seem extremely far from what you think the answer is ● Use use the information given to you, but remember that not all of it is always useful ○ Sometimes, questions are testing your ability to pick out most useful information ● MC question applications specic to Unit 4 ○ Visualize molecules with correct orientation ○ Use conceptual checks when dealing with energy distribution graph proles ○ Use shorthand stoichiometry to nd rates when given at equation ○ Remember what effects what (EX: Activation energy doesn't depend on temperature)

○ When concentrations are doubled, double the order and multiply them to nd overall ○ Resort to table logic when given a table and look for hints like ln or 1/[A] ○ Remember basic denitions (EX: Catalysts do not get consumed...


Similar Free PDFs