Assessment 2 PDF

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Building 1 assessment 2...

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Section 1: Using the tables from AS1684, calculate the minimum size of the nominated timber members which will act as a uniform construction for the Elevation 4 wall frame of your project home. NB: Drawings indicate a tiled, trussed roof @ 22½0 pitch. Assume studs at 450mm centres. Use only SEASONED timber as nominated and DO NOT use alternative sections as noted in Table A1. Q1/ stud 70mmx75 wall stud frame the stud supporting the structure 450 mm centred Table number: A9 Timber grade: F8 In order to calculate the wall height, we need to add the thickness of the top and bottom plates to the actual height Wall height = 2450mm - (2 * 45mm+ 2 * 45mm) (Thickness of the top plates and bottom plates) =2270mm Roof type= Tile, Notched Timber type = Seasoned Use 2400mm Span 9480mm (4070+70+5340) but we will Use: 12000mm ANSWER Material f8 2/70mmx35mm given the stud that have less pressure on it

Q2/ Bottom plate Table number: A20 Timber type: seasoned, Not trenched Timber grade: F17 seasoned Studs spacing: 450mm centres Roof type: Tile Roof span is 9480mm (family room have a consistent roof 4070+70+5340) =9480mm Because its greater than 9000mm we will use 12000mm. Therefore, the answer is 2/45mm*70mm

Q3/ Top plates: Table Number: A22 Timber Grade: MGP12 Timber Type: Not trenched, Seasoned Roof Type: Tile Spacing: 450mm centred Span: 9480mm (4070+70+5340) but we will Use: 12000mm ANSWER 2/45mm*70mm

Q4/ jamb stud’s laundry Table number: A15 Opening: 910mm Total opening width = 910mm+(35mm+35mm) (Bearings) =980mm so its greater than 900mm thus we will use 1200mm instead. Timber Type: Seasoned Roof Type: Tile Span: 9480mm (4070+70+5340) but we will Use: 12000mm Timber grade: MGP12 ANSWER 2/70mmx35mm

Q5/ Lintel to Dining Room window Table number: A24 Timber Type: Seasoned. Roof Type: Tile. Timber grade: MGP10. Lintel to Dining Room window with assumed opening of 2110mm Total Opening dinning window = 2110mm + (35 + 35) (Bearings)=2180 Truss Span: 9480mm (4070+70+5340) but we will Use: 12000mm ANSWER 2/240mmx35mm

Q6/ The order length The total window opening = 2110 + 70 (Bearing), the Timbers sold size range = 2400mm > 3000mm, the appropriate length is 2400mm to then be cut down to the perfect size. The commercial timber is sold in multiples of 300mm ANSWER 2 0f 2.4 metre OR 1 of 4.8 metre

Q7/ Part 1: Overhang spacing according to section A-A is 450mm. find the rafter span using site plan including adding measurements and excluding overhangs: 4000 + 220 +1650+ 175 – 35 =6010 divide by 2 = 3005 divide by cos (22.5) = 3252mm divide by 2=3252.6 mm

In order to find the span. 3252.6 divided by 2 = 1626.29mm

Part 2: Overhang = Eave+brick width+ gap The L of the overhang = 450 +110+40 =600divide by cos22.5 = the total overhang =649.25 Part 3 and 4: Rafter span = 1626mm (1800mm) Roof type= tile Type of timber = seasoned

Timber grade= MGP 12 Spacing= 450mm Table= A34 Therefore, the nominated timber size is= 90mm*35mm Nominated overhang size required is 700mm

Q8/ Underpurlin Table number =13 Type of roof = Tile Continues span = 2.4 mm (2400mm) RLW= 1626+1626= 3252 divided by 2 = 1626 thus we will use (1.8) continues span is 2400 spacing = 3.2 according to the Table (13) the Breadth and depth are = 130mm * 63mm

Q9/ Collar tie Collar tie equals span of rafter, which means collar tie = total span divided by 2 Therefore = 3005 Table number 7.6 Order length = 3600 mm Ties to 4200mm longer for less than F8/MGP12 stress grade = Member size = 70mm*35mm or 90mm*35mm Q10 Table number: 11 Ceiling joist spacing = 450mm Span =2490mm-2525mm Breadth and depth=90mm* 35mm

Q11. Note make sure you include the drawing: To choose which option need to calculate the height of the roof Truss span of section A-A:4070+70+5340=9480 Pitch 22.5” Side angle = Tan 22.5 = (0.5/9480) x height H=4740x tan22.5=1963.3 Total height= 2450+1963 =4413mm < 4500mm

Wind direction north and south 3and 1 are acting the same length of the house wind classification N 2 found on elevation roof table (because the it has high roof pitch) Table 8.2 Wind class =n2 Type of construction = single storey Total number of A type bracing units Require 5 type A bracing units Use option s1: length of 6000. Height 4500 5* (13300 total wall length+1890 garage/ 6000(s1)) =12.7 Use :13 13 Type A Bracings Wind direction west and east 2 and 4 5* (21680/6000) =18,06 Use 18 18 Type A Bracings

Q12/ According to 8.3.2.3 standards 1 type B =2 Type A ELEVATION 1/3 13=2A+A TYPE A=3/13=4.3= 5 ROUND UP 13-5=8 /2 TYPE B = 8/2= 4 Type B ELEVATION 4/2 18 USE = TYPE A=18/3= 6 Type A 18-6=12 TYPE B = 12/2= 6 Type B

Working out Ceiling height =2450 Pitch of roof= 22.5 D Truss spam= 2500+ 1500 +1400+3870+70=9480 Roof height= (9480/2=4740)

=2450+1963=4413=total h

Section 3: Q13/ Bottom plates to floor frame or slab. Table 9.6 Joint or member: Bottom plates to floor frame or slab. Span = 9480mm we will round it up to 12000mm Wind classifications: N2 Spacing: 1800mm Answer 30 * 0.8mm G.I. strap 6/30 * 2.8mm dimeter nails each end or M10 Masonry anchor Q14/ Top and bottom Plates to studs Table 9.6 Wind classification N2 Span = 9480mm we will round it up to 12000mm Joint or member: Top and bottom Plates to studs Answer: 30 * 0.8mm G.I. strap at 1200mm max. Centres along wall 6/30 * 2.8mm dimeter nails to each end of strap. Q15/ Rafters to Top plates, beams or studs- coupled roofs- no Ridge tie-down Continuous rafter to top plate with a rafter spacing of 600mm (NB: no ridge tie-down). Table 9.6 Rafter span: 3000 (continuous) Rafter spacing: 600mm Answer: 30 * 0.8mm G.I. strap or one framing anchor....