BIOL100 Prelab 1 Hunter College Fall 2019 PDF

Title BIOL100 Prelab 1 Hunter College Fall 2019
Author Dibisha Roy Biswas
Course Biology
Institution Hunter College CUNY
Pages 1
File Size 137.2 KB
File Type PDF
Total Downloads 80
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Summary

Prelab for bio 100 relating to the beginning chapters of study...


Description

Name: Dibisha Roy

EMPLID: 23911332

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1. What determines the property of a polypeptide? Polypeptides are composed of amino acids where each amino acid consists of a central carbon bound to an amino group on one side and a carboxyl group on another. The central carbon is bound to a hydrogen atom and an unique sude chain or R group that makes each of the twenty amino acids found in polypeptide differ from one another which further determine the properties of a polypeptide.

2. Indicate your substrate for the Enzymes I experiment. What will the enzyme do to the substrate? The substrate in the Enzymes 1 experiment is para-nitrophenyl phosphate which consists of a six carbon ring (benzane) with one end of the ring covalently bonded with a phosphate while the other end of the ring is covalently bonded with a nitrate group. The addition of the enzyme, acid phosphate, will allow a water molecule to be introduced between the phosphorus atom and the oxygen atom that links the phosphate group to the benzene ring, and it will break the covalent bond. In simple word it would speed up the reaction so that we can measure product formation during the lab period.

3. How do you determine the micromoles of product seen at the end of your reaction? To determine the micromoles of product seen at the end of the reaction, we have to find the standard curve, using a spectrophotometer. We first have to find the measured absorbance for the sample on the y-axis, then use a straigh edge to trace the value horizontally to where it intersects the line for the standard curve, then place the straight edge at right angles to that point, and finally trace down to the point where it intersects the x-axis.

4. What is the specific difference between E tubes and C tubes? The specific difference between the E tubes and C tubes are that the E tubes will receive samples from the "experimental" part, while the C tubes receive samples from the "control" part of te time course, so they don't receive an enzyme to react with.

5. What purpose does the citrate buffer serve? The purpose of the citrate buffer is to allow the enzyme to go through a conformational change, which puts stress on existing bonds within the substrate that must be broken down while fostering new bonds that have to be made in order for a substrate to be converted into product, and to get more product. It also prevents the enzyme from changing before the end of the reaction since the enzyme being used int he experiment is acid phosphatase. Overall, citrate buffer also has alkanizing properties which make it not as susceptible to pH change with the additio of the substrate which is crucual to the experiment.

Pre-lab assignment #3 – Enzymes I...


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