Examen final Microeconomía II PDF

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Examen final corregido de la asignatura Microeconomía II (UPF)...

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y

p(y) = 28 − (y/25) p C(y) = 4y + (y 2 /50)

y(p) = 60 − p

C(y) =

y2 2

y = 160 − 4p p

y

y y = 10l

p(y) = 4200 − y

l 100

p Ci (yi ) = y 2i

y1 = 1050

y2 = 1050

y1 = 1200 y2 = 1200

y1 = 840 y2 = 840 y1 = 1400

y2 = 700

y1 = 735 y2 = 1260. y1 = 1260

y2 = 735.

y1 = 1400

y2 = 700.

y1 = 900 y2 = 825.

4 ya = 100 − 10p a pe

pa

pa = 2 pa = 7

p a = 12 p e = 7

p e = 17 p e = 12

p a = 9.50

ye = 200 − 2p e

p e = 9.50 p a = 10 − y10a

p e = 100 − y2e

4

max (10 −

ye )ye − 4ya − 4ye 2 100− 2y2e −4 = 0 F OCye −4 = 0 96 p e = 100 − 2 = 52

(y a ,y e )

F OCya

(100 − 2y a 10

p=2

ya )ya + 10

ya = 30

10 −

30 p a = 10− 10 =7

ye = 96

p = 12

p=7 p = 9, 50

y = 300 − 12p

p ≤ 10 p≥ y = 200 − p = (300−y)/12 p = 100− 300/12−2y/12−

10 2p y 2

−4 = 0 100− 2y 2 π = 1323

4=0 14.5 > 10 10

y = 126 y = 96

p = 52

p = 52

p = 174/12 = p > π = 2496

1 , x2 ) = min{x1 , x2 } uA (xA A A A 1 10 2

A B 1 , x2 ) = x1 + x2 uB (xB B B B

1 x2A = xA

x1A = 10 x1A = 0 x2A = 2xA1

2 = x1 xA A

A

1 x2A = xA

1 , x2 ) = (6, 4) (xA A

A

uB (6, 4) = 10

B

B

A

A

B

A ΩA = (6, 4) uA (6, 4) = uA (4, 6) = 4 A B A ΩA = (6, 4)

B

A

B B

ΩA = (4, 6) B uB (4, 6) = 2 = x1 xA A

1 , x2 ) = 5 log(x1 ) + 5 log(x2 ) uA (xA A A A

A B 2 )1/2 uB (x1B , x2B ) = (x1B )1/2 (xB

x2A =

1 xA 4

x2A =

1 xA 6

(12, 3)

x2A = 4xA1 1

x2A = 1xA x −8 A

MRSA = 2 xA 1 xA

=

2 xB 1 xB

A A x1A = 0 x1A = 2

x2 B 1 xB

x1B = 12 − 2 xA

3−x2A 1 = 12−x1 xA A x1 x2A = 4A

2 2 1 2 12xA − x1A xA = 3x1A − xA xA

(x1A , x2A )

MRSB =

Ω = (12, 3)

x1A yx2B = 3−x2A 1 1 2) x2A (12 − xA ) = xA (3 − xA

2 xA 1 xA

1

= (4, 8)

2

p1 = 1

p2 = 1

1 xA =5

x1A = 4.5 MRS = 2 xA 1 xA

12

1 xA

=1 x2A

=

= 12 −

x2A 1 xA

p1 p2

A MRSA = xA1 + x2A =

A x1A

= 12 −

1 xA

x1A = 6

s x

a

CS (s, x) = s2 + 2(x − 6)2 CA (A, x) = 2a2 + 4x. Ps = 200

s = 40 a = 25 s = 50 a = 30 s = 90 a = 25

Pa = 100

s = 80 a = 30

x=7

S 200 − 2s = 0 A 100 − 4a = 0

x=4

x=6 x=6 πS = 200s − s2 − 2(x − 6)2 x−6 = 0 s = 100 πA = 100a− 2a2 − 4x

a = 25

t

x

t=2

t

x

t=4

∂CA ∂x

=4 t=4

x = 6

G i

xi

i

u(xi , G) = 4xi + 3 log G

G G G∗ G∗ = 5

G∗ = 3/100(= 0.03) G∗ = 30/106(≈ 0.28) G∗ = 3

Ui = 3 log G + 4x

G MC = 15+10

P

MRS = M C

100

3/G 4

= 25

G=3

x

≻ y≻z≻x

≻ y≻z≻x

x

z

y≻z≻x

uA = xA

uB = 4(xB )1/2

x

W (uA , uB ) = uA + uB

uB

xB = 300 − xA 4 =0 1 − 2(300−x )1/2 A

xA +xB = 300 xB = 300−xA maxxA xA + 4(300 − xA )1/2 xA = 296

maxxA ,xB uA +

1 1 2 uA (xA , x2A ) = xA + xA

uA = 50

uB = 0

uA = 25

uB = 250

uA = 45

uB = 50

A 1 uB = 10(xB + x2B )

B

xA = (30, 20)

(30, 20) xB = (0, 0)

xA = (15, 10) xA = (27, 18)

xB = (15, 10) xB = (3, 2)

Q q1 = q2 = Q/2

ǫ...