Level 2 chem revision - lllllll PDF

Title Level 2 chem revision - lllllll
Author Lauren Dressler
Course Analytical Chemistry
Institution University of Waikato
Pages 6
File Size 141.4 KB
File Type PDF
Total Downloads 78
Total Views 119

Summary

lllllll...


Description

 No Brain Too Small  CHEMISTRY  AS 91165

Orga Organic nic Reac Reactio tio tions ns by ty type pe     

Substitution Addition Elimination Oxidation Acid-base

As you study the different functional groups, and meet the reactions on the following pages tick the boxes 

 No Brain Too Small  CHEMISTRY  AS 91165

Substitution An atom is replaced by another atom/group • •

The organic product is (still) saturated Two products are made

Alkanes:  Alkane to Haloalkane • React with Br2 or Cl2. Needs uv light and/or heat to occur. (It doesn’t matter which H you substitute in the formula but limit it to just one @ L2). CH3CH3 + Br2  CH3CH2Br + HBr

Haloalkanes:  Haloalkane to Alcohol • React with KOH(aq), heat. CH3CH2Br  CH3CH2OH  Haloalkane to Amine • React with Conc. NH3(alc) CH3CH2Br  CH3CH2NH2

We do not normally worry about the other product made in these reactions, just the organic product.

 No Brain Too Small  CHEMISTRY  AS 91165

Addition One bond of the C=C bond breaks and an atom/group adds onto each of the two adjacent C atoms. (Often written as the C=C bond breaks and 2 atoms/groups add on). • • •

The organic product is saturated One product is made If the alkene is asymmetrical and the reagent is asymmetrical then a major and minor product is made. Remember “rich get richer” where the H is added to the C of the C=C which originally had most H atoms.

 Alkene to Alkane • H2, Ni or Pt catalyst CH2=CH2 + H2  CH3CH3  Alkene to Haloalkane • Br2 or Cl2 CH2=CH2 + Br2  CH2BrCH2Br • HBr or HCl CH2=CH2 + HCl  CH3CH2Cl  Alkene to Alcohol • H2O/H+, heat (or dilute acid, heat) CH2=CH2 + H2O  CH3CH2OH  Alkene to (addition) Polymer • Ethene monomers, heat and catalyst, e.g. 3 repeating units 3CH2=CH2  -(CH2-CH2)-3

 No Brain Too Small  CHEMISTRY  AS 91165

Elimination An H atom and an atom/group are removed from two adjacent carbon atoms. • • •

The organic product is unsaturated / has a C=C Two products are made (but we are interested in the organic one) If the alcohol or haloalkane is asymmetrical then a major and minor product is made. Remember “poor get poorer” where the H is removed from the C atom which originally had least H atoms.

 Alcohol to Alkene • Conc. H2SO4 CH3CH2OH  CH2=CH2 (H2O is removed / dehydration reaction)

 Haloalkane to Alkene • KOH(alc), heat CH3CH2Cl CH2=CH2 (HCl is removed) CH3CH2Br CH2=CH2 (HBr is removed)

 No Brain Too Small  CHEMISTRY  AS 91165

Oxidation This group don’t look like they have much in common but they all involve an oxidation reaction (reaction with an oxidising agent). There is always an accompanying reduction reaction (so the reactions are REDOX reactions).  Combustion (burning) • Alkanes, alkenes, alkynes, alcohols etc are all flammable. Any “burning” reaction is an “oxidation” reaction. C3H8 + 5O2  3CO2 + 4H2O

 Alkene to Diol • Uses potassium permanganate, KMnO4. • No heat is needed. The MnO4- ion has a purple colour. CH2=CH2  CH2OHCH2OH • •

If MnO4- with no acid, MnO4- is reduced to brown MnO2(s) If MnO4-/H+, MnO4- is reduced to colourless Mn2+(aq)

 (Primary) Alcohol to Carboxylic Acid • With MnO4-/H+, heat (colour change - purple MnO4-(aq) to colourless Mn2+(aq)) OR • With Cr2O72-/H+, heat (colour change - orange Cr2O72-(aq) to green Cr3+(aq)) C2H5OH  CH3COOH

 No Brain Too Small  CHEMISTRY  AS 91165

Acid-base At L2 the only organic acids are carboxylic acids e.g. CH3COOH AND the only organic bases are amines e.g. CH3CH2NH2.  Reactions of Carboxylic Acids • With H2O (explaining why carboxylic acids are acidic) CH3COOH + H2O ⇌ CH3COO- + H3O+ • • •

With Mg (a reactive metal) 2CH3COOH + Mg  (CH3COO)2Mg + H2 With NaOH CH3COOH + NaOH  CH3COONa + H2O With NaHCO3 CH3COOH + NaHCO3  CH3COONa + H2O + CO2



With Na2CO3 (OR with CaCO3, marble chips) 2CH3COOH + Na2CO3  2CH3COONa + H2O + CO2 2CH3COOH + CaCO3  (CH3COO)2Ca + 2H2O + CO2

Note: CH3COONa is often written as CH3COO- Na+  Reactions of Amines • With H2O (explaining why amines are basic) CH3CH2NH2 + H2O ⇌ CH3CH2NH3+ + OH•

With HCl (acid) CH3CH2NH2 + HCl  CH2CH2NH3+Cl- (a salt)

 Reaction of Carboxylic Acid and Amine (In 2017 exam; not usually asked!) • CH3COOH + CH3CH2NH2  CH3CONHCH2CH3 + H2O OR CH3COOH(aq) + CH3CH2NH2(aq)  CH3COO- (aq) + CH3CH2NH3+ (aq)...


Similar Free PDFs