S08.s1 - Repaso Examen parcial -2009 042417 PDF

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■◆❚❘❖❉❯❈❈■Ó◆❆▲❆▼❆❚❊▼➪❚■❈❆P❆❘❆▲❆■◆●❊◆■❊❘❮❆▼❆❚❊❘■❆▲❉❊❘❊P❆❙❖❊❳❆▼❊◆P❆❘❈■❆▲❊❏❊❘❈■❈■❖❙P❘❖P❯❊❙❚❖❙✶✳ ❯♥❥♦②❡r♦t✐❡♥❡tr❡s❝❧❛s❡s❞❡♠♦♥❡❞❛s❆✱❇②❈✳▲❛s♠♦♥❡❞❛s❞❡t✐♣ ♦❆t✐❡♥❡♥✷❣r❛♠♦s❞❡♦r♦✱✹❣r❛♠♦s ❞❡♣❧❛t❛②✶✹❣r❛♠♦s❞❡❝♦❜r❡❀❧❛s❞❡t✐♣ ♦❇t✐❡♥❡♥✻❣r❛♠♦s❞❡♦r♦✱✹❣r❛♠♦s❞❡♣❧❛t❛②✶✵❣r❛♠♦s❞❡ ❝♦❜r❡✱②❧❛s❞❡t✐♣ ♦❈t✐❡♥❡♥✽❣r❛♠♦s❞❡♦r♦✱✻❣r❛♠♦s...

Description

− → − → a = (x +1; 3x −3) b = (1−x)i+xj − → R = (3x; x + 3) L1 : 3x + (m − 1 )y = 7 − 2n L2 : 4y = x − 4

m

(−1, 0, 3)

L1

(3, −2, 5)

x ∈Z

(3 , −1 ) n L2 : P = (−2, 1, 0) +

t (4, 0, −1) L1

L1 :

x −3 2

=

1 −y 5

=z +1

L2   x = 1 + 2r y = −2 + 3r L2 :  z = −r

P (2 ; 1 ; −1 )

L1 : x−2 5 =

2−y 4

= 2z − 4

A (5 , 1 , −1 ) = L1 : 2x+4 4

y−3 −1

=

z+2 5

A(1 , −3 , 2 ) B (0 , 1 , 1 ) L2 :



3x − 2y + 1 = 0 2x + 3z − 3 = 0 (0, −2, 5)

(−1, 3, 1)

2z = 5x + 4y

x = 5;

y = 3;

x = 130 ; 7

5 4; −8

√7 53



z =2

y = 160 ;

z = 50

PI (3 ; 1 ; −1 ) 86 83 167 ; ; 33 33 33  x = 5 − 56t y = 1 + 13t  z = −1 + 25t P: − 7x − 10y − 33z + 43 = 0 P : 6x − 22y − 29z + 101 = 0...