Title | Solucion de la pregunta del armado del parcial 2021-01 |
---|---|
Author | Julio Herrera Vera |
Course | Analisis estructural 2 |
Institution | Universidad Peruana de Ciencias Aplicadas |
Pages | 1 |
File Size | 87.4 KB |
File Type | |
Total Downloads | 23 |
Total Views | 550 |
Download Solucion de la pregunta del armado del parcial 2021-01 PDF
Examen Tipo
Elem 1
EA
1000
y 0 17 17 5
A 5
B 5
C 12
D 5.00
Elem 1 2 3 4 5
Dir Arriba Derecha Derecha Derecha Derecha
Δx 0 10 5 5 5
Δy 17 0 5 -12 12
Elem 3 K
4 0 0 0 58.8235294 0 0 0 -58.823529
5
1
K=
x 0 0 10 5
Elem 2 K
3
Nudo 1 Nudo 2 Nudo 3 Nudo 4
A
93.47 70.71 -70.71 -70.71 -11.38 27.31 -11.38 -27.31
6 0 0 0 -58.823529 0 0 0 58.8235294
5
6
7
8
0 0 0 0
-100 0 100 0
0 0 0 0
6 27.31 -65.54 0.00 -58.82 -27.31 124.37 0.00 0.00
7 -11.38 -27.31 0.00 0.00 -100.00 0.00 111.38 27.31
8 -27.31 -65.54 0.00 0.00 0.00 0.00 27.31 65.54
2 70.71 201.80 -70.71 -70.71 27.31 -65.54 -27.31 -65.54
3 -70.71 -70.71 70.71 70.71 0.00 0.00 0.00 0.00
4 -70.71 -70.71 70.71 129.53 0.00 -58.82 0.00 0.00
5 -11.38 27.31 0.00 0.00 111.38 -27.31 -100.00 0.00
0.707
0.707
-0.707
-0.707
*
0.385
0.923
-0.385
-0.923
*
f3
f5
0.48210 0 0.43498381 -0.02289 0.43498381 -0.0228854 0 0
3 70.711 70.711 -70.711 -70.711
F=
=
7.0000
=
1.124E+01
4.95 -7.95 4.95 R4 R5 R6 R7 R8
L 17 10.00 7.07 13.00 13.00
EA/L 58.8 100.0 141.4 76.9 76.9
cos 0 1.000 0.707 0.385 0.385
Inclinada 7
sen 1 0.000 0.707 -0.923 0.923
Elem 4 K
100 0 -100 0
Carga 3
Elem 5 K
4 70.711 70.711 -70.711 -70.711
1 -70.711 -70.711 70.711 70.711
2 -70.711 -70.711 70.711 70.711
d=
0.43498381 -0.02289 0.48210
Pu=
4.94974747 -5.5747475 13.3793939 -4.3247475 -10.379394
5 11.379 -27.310 -11.379 27.310
6 -27.310 65.544 27.310 -65.544
1 -11.379 27.310 11.379 -27.310
2 27.310 -65.544 -27.310 65.544
K 1 11.379 27.310 -11.379 -27.310
2 27.310 65.544 -27.310 -65.544
7 -11.379 -27.310 11.379 27.310
8 -27.310 -65.544 27.310 65.544...