Title | Tableof Useful Integrals |
---|---|
Author | Alexander Ng |
Course | Quantum Theory |
Institution | St. John's University |
Pages | 6 |
File Size | 1.1 MB |
File Type | |
Total Downloads | 50 |
Total Views | 145 |
Download Tableof Useful Integrals PDF
Table of Useful Integrals, etc. 1
∞
∫e
− ax 2
0
∞
1 π 2 dx = 2 a
− ax 2
∫ xe 0
1
∞ 2 − ax 2
∫x e 0
2n − ax 2
∫x e 0
n − ax
3 − ax 2
∫x e
dx =
0
dx =
0
(
)
1
1⋅ 3⋅ 5 ⋅ ⋅ ⋅ 2n − 1 π 2 dx = 2 n+1 a n a
∞
∫x e
∞
1 π 2 dx = 4a a
∞
dx =
1 2a
1 2a 2
∞
∫x
2n+1 − ax 2
e
0
dx =
n! 2a n+1
n! a n+1
Integration by Parts: b
b b
∫UdV = UV a− ∫VdU a
U and V are functions of x. Integrate from x = a to x = b
a
1
∫sin (ax )dx = − a cos ( ax ) x
∫sin (ax ) dx = 2 − 2
( )
sin 2ax 4a
1
1
∫sin (ax ) dx = − a cos ( ax ) + 3a cos ( ax ) 3
3
( )
( )
( )
3 3x 3sin 2ax sin ax cos ax ∫sin ax dx = 8 − 16a − 4a 4
( )
( (
) )
( (
) )
( ) ( )
sin a − b x− sin a + b x where a 2 ≠ b2 2 a+b 2 a−b
( ) ( )
sin a − b x + sin a + b x 2 a+b 2 a−b
∫sin ax sin bx dx =
∫cos ax cos bx dx =
( (
) )
( (
) )
(
( ) ( ) 2
(
( )
2 2 ∫ x sin ax dx =
( )
( (
) )
(
)
(
)
(
( ) − x cos( ax)
a2
a
( ) + cos ( ax )
x sin ax
( )
∫cos (ax ) dx =
( )
sin ax a x
2
a2
a
∫cos (ax ) dx = 2 +
( )
2 2 ∫ x cos ax dx =
( )
sin 2ax 4a
Taylor Series: ( n) xo n= ∞ f
( )
( )
eax
(a
2
(x−x )
Geometric Series: ∞ 1 ∑ xn = 1 − x n=0
( )
x cos 2ax 1 x 3 x 2 + − 3 sin 2ax+ 6 4a 8a 4a 2
2
− ax ∫cos bx e dx =
o
(
)
(
)
cos a − b x − cos a + b x+ x sin a − b x − x sin a + b x 2 2 2 2 2 a−b 2 a−b 2 a+b 2 a+b
sin ax
∫ x cos ax dx =
n!
( )
( )
( ) ( )
n=0
) )
x cos 2ax x 3 x 2 1 − − 3 sin 2ax− 6 4a 8a 4a 2
∫ x sin ax sin bx dx =
∑
)
( )
( )
( )
( (
cos 2ax x 2 x sin 2ax − − 4 4a 8a 2
∫ x sin ax dx =
∫ x sin (ax ) dx =
)
− cos a − b x − cos a + b x 2 a+b 2 a−b
∫sin ax cos bx dx =
( )
( )
a cos bx + bsin bx + b2
)
n
)
(
)
Euler’s Formula: eiφ = cos φ + isin φ Quadratic Equation and other higher order polynomials: ax 2 + bx + c = 0 x=
−b ± b2 − 4ac 2a
ax 4 + bx 2 + c = 0 −b ± b2 − 4ac x = ± 2a General Solution for a Second Order Homogeneous Differential Equation with Constant Coefficients: If: y ′′+ py ′+ qy = 0 Assume a solution for y: y = esx y ′= sesx y ′′= s 2 esx ∴ s 2 esx + psesx + qesx = 0 and
s 2 + ps + q = 0
Hence
sx
s x
y = c1e 1 + c2 e 2
Conversions from spherical polar coordinates into Cartesian coordinates:
x = r sin θ cos φ y = r sinθ sin φ x = r cos θ dv = r 2 sinθ drdθ dφ 0...