Title | Tổng hợp công thức SB |
---|---|
Author | Phương Anh Phạm Ngọc |
Course | Statistics for Business |
Institution | Trường Đại học Kinh tế Thành phố Hồ Chí Minh |
Pages | 11 |
File Size | 815.2 KB |
File Type | |
Total Downloads | 4 |
Total Views | 1,091 |
MATERIALS SB####### CHAPTER 1 Descriptive data and Inferential Data Critical thinking Conclusion from small samples Conclusion from non-random samples Conclusion from rare event Poor survey methods Post-hoc fallacy CHAPTER 2 Level of measurement Nominal measurement Ordinal measurement Interval ...
MATERIALS SB CHAPTER 1 Descriptive data and Inferential Data Critical thinking + Conclusion from small samples + Conclusion from non-random samples + Conclusion from rare event + Poor survey methods + Post-hoc fallacy CHAPTER 2 Level of measurement + Nominal measurement + Ordinal measurement + Interval measurement + Ratio measurement Sampling method + Simple random sample + Systematic sample + Stratified sample
Random sampling method
+ Cluster sample + Judgment sample + Convenience sample
Non-random sampling method
+ Focus group CHAPTER 3 Steam and leaf Dot plot Sturges’ Rule: k
Bin width
(¿ n) ¿ 1+3.3 log ¿
xmax xmin k
Histogram and shape
CHAPTER 4: Descriptive Statistics n
Sample mean:
´x
=
1 ∑ x : Trung bình cộng n i=1 i
Median: middle value Mode: Frequent value Geometric mean: G =
√ x1 x2 … xn n
:Trung bình nhân
Range: R = x max−x min : khoảng Midrange =
x min + x max 2
:khoảng cách trung bình
Mode luôn lớn nhất, nếu mean< median: skewed left; mean=median: Symmetric; mean>median: skewed right Sample variance: Phương sai =
¿ Population: σ 2 , Sample: s 2 ) 2 s ¿
Sample standard deviation: s =
√
n
2 (x i− ´x ) ∑ :Độ lệch chuẩn i=1
n−1
Coefficient of variation of population:để so sánh 2 giá trị ko cùng đơn vị CV = 100 ×
σ μ
; CV of sample: CV = 100 ×
Chebysev’s Theorem:
s ´x
(S: độ lệch chuẩn ,X: mean )
percentage ( nhận biết at least )=1−
Empirical Rule: (nhận biết: Normal Distribution)
1 k2
k: khoảng
Standardized variable of population:
z i=
x i−μ σ
; of sample: z i=
x i− x´ s
n
∑ (x i−´x )( y i− ´y ) Sample correlation coefficient : r
=
i=1
√
n
∑ (xi− ´x )2 i=1
First quartile position :
√∑ n
2
( y i− y´ )
i =1
Q1 = (n+1) /4
Second quartile position: Q2 = (n+1)/2 (the median position)
Third quartile position:
Q3 = 3(n+1)/4
where n is the number of observed values Midhinge =
Q 1 +Q 3 2
Nếu midhingeq2: skewed right IQR= Q 3−Q 1 Fences and Unusual Data Values Lower fence Upper fence
Z score=
Inner fences Q1 – 1.5(Q3 – Q1) Q3 + 1.5(Q3 – Q1)
Outer fences Q1 – 3(Q3 – Q1) Q3 + 3(Q3 – Q1)
x−μ x−´x = s σ
Cách bấm máy: Tính mean ,median ,q1,q2,s…Mode 6 -> 1-> 3 Tính R:
Mode6 2 4
CHAPTER 5: Probability Event: biến cố
P(s)= P(E1)+p(E2)+….+P(En)=1 Complement of an event: (Phần bù): P ( A )=1−P (A ' ) Union: hợp (hoặc) Intersection: giao (và) ( joint probability) If A ∩ B = ∅ (exclusive or disjoint), then P(A ∩ Odds for A:
P( A) ; Odds against A: 1−P( A)
B) = 0(null)
1−P( A) P( A)
General Law of Addition: P ( A ∪ B ) (hợp )=P ( A ) + P ( B ) −P ( A ∩ B) (giao) Conditional probability:
P ( A|B ) =
P( A ∩ B) P(B)
:Sác xuất điều kiện
Two events are independent if and only if: P ( A|B )= P( A) Independence property: P ( A ∩ B) =P( A ) . P(B) Bayes’ Theorem: P (B|A ) =
P ( A∨B). P(B ) ' ' P ( A∨ B ). P ( B )+ P ( A∨B ). P ( B )
Permutation : nPr
=
n! (n−r )!
Combination: nCr
=
n! r ! (n−r) !
CHAPTER 6: Discrete Probability Distributions Probability Distribution Function (PDF) shows the probability for each value: P(x)≥ 0 ;
∑ P(x )=1 x
Cumulative Probability Function (CDF), denoted F(x0), shows the probability that X is less than or equal to x0 F ( x 0 )=P (X ≤ x 0 ) Expected value: (giá trị kì vọng):
;
F ( x 0 )= ∑ P (x) x ≤ x0
μ= E ( x )=∑ xP (x) x
Bài toán vé số = (value win) x P(win) + (value lose) x P(lose) Variance of a discrete random variable X:
2 2 2 σ =E(x−μ) =∑ ( x−μ ) P ( x ) ;
σ 2 =E ( x2 )−μ2
a: lower limit; b: upper limit; n (số số hạng)=b-a+1
x
Uniform PDF: P(X =x)
=
1 1 = b−a+1 n
;
x=a , a+1 , … , b
Bernoulli (Thành công hay thất bại nhưng chỉ với 2 outcomes) (kí hiệu:success x=1;failure x=0)(P(success)= π ; P(failure)= 1−π )( π...