Final exam study guide notes chm1046 PDF

Title Final exam study guide notes chm1046
Author Anonymous User
Course Chemistry 2
Institution Florida State University
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Summary

chem notes for the final exam and cumulative information from the whole course. Really helpful when I took it...


Description

Lecture 1: Part 1: Intermolecular Forces 

Describe the types of intermolecular forces possible between atoms or molecules in condensed phases (dispersion forces, dipole-dipole attractions, and hydrogen bonding) o

Dispersion forces 

Dispersion Forces: The force of attraction between an instantaneous dipole and an induced dipole.



Polarizability: Measure of ease with which electron charge density is distorted by an external electrical field: reflects the facility with which a dipole can be induced. 

The greater the polarizability of molecules, the stronger the intermolecular forces between them



Larger molecules are more polar because the outer electrons are more loosely bound in larger molecules than smaller molecules so they have greater polarizability



The higher the atom and molecular masses, the higher the polarizability and intermolecular forces



Elongated Molecules vs Compact Molecules 

Elongated have greater intermolecular forces because they cover a greater distance

o

Dipole-Dipole attractions 

Dipole-Dipole Attraction: When opposite charges, the positive dipole and the negative dipole, on neighboring molecules to attract each other



Polar molecules have a: permanent separation of charge within their bonds



Permanent Dipole: When one end of the molecule is electron deficient with a partial positive charge (δ+), while the other end is electron rich with a partial negative charge (δ−)



The strength of the intermolecular force depends on what? 



The distance and the relative orientation of the dipoles

What is a property of polar compounds when compared to non-polar compounds of similar molecular masses? 



Higher melting and boiling points

Dipole-Dipole forces are stronger than this other force: London Dispersion Forces



o

What types of compounds does Dipole-Dipole attraction occur between?  Any polar compounds Hydrogen Bonding 

Hydrogen Bond Definition: attraction between a highly electronegative atom in one polar bond and a slightly positive hydrogen atom in another polar bond



Qualities that water has due to the hydrogen bonds: 

High heat capacity



High heat of evaporation



High cohesion surface tension



Excellent solvent for other polar molecules



Hydrophilic interactions: h- bonds can form between any 2 polar molecules



Hydrophobic interactions: non polar molecules (cannot dissolve in water)



Why do strong ionic attractions dissolve in water?



In the presence of water, attractions between ions can be "replaced" by attractions to the + or - ends of waters polar bonds, so salts dissolve easily in water



Identify the types of intermolecular forces experienced by specific molecules based on their structures o

The structure of a molecule plays a very important role in determining its intermolecular forces and its chemical properties.

o

The method we will be using to predict the shape, or geometry, of a molecule is called the valence shell electron pair repulsion (VSEPR) theory.

o

The VSEPR theory is about geometry of compounds and electron location. Electron pairs in a molecule repel one another; therefore, electrons will distribute themselves in positions around the central atom that are as far away from each other as possible.

o

The number of electron pairs, non-shared electron pairs, and shared electron pairs, in the valence energy level of the central atom determines the shape of a molecule. The VSEPR shape of a molecule can be determined after drawing a Lewis dot structure.

o

o

London dispersion forces: 

Experienced by all molecules and particles.



Weakest intermolecular force.



Examples: Ne, O2, CO2.

Dipole-dipole forces: 

Experienced by all polar molecules.



The strength depends on the difference in electronegativity between the two atoms.



Examples: H2S, SO2.

o

Hydrogen bonding: 

Experienced by polar molecules in which hydrogen is covalently bonded to a highly electronegative element.



A particularly strong dipole-dipole force where a H atom in one molecule is electrostatically attracted to the N, O, or F atom in another molecule.

 o

Examples: HF, H2O, NH3, alcohols, and macromolecules.

Ion-dipole forces: 

Experienced by ions interacting with polar molecules in solution.



They become the stronger as either the charge on the ion increases or as the magnitude of the dipole of the polar molecule increases.

 

Examples: NaCl + H2O.

Explain the relation between the intermolecular forces present within a substance and the temperatures associated with changes in its physical state o

Lower temperatures: stronger intermolecular forces

o

Higher temperatures: weaker intermolecular forces

Part 2: Properties of Liquids 



Distinguish between adhesive and cohesive forces o

Adhesive forces are between unlike substances

o

Cohesive forces are between like substances.

o

(glue to paper//water to water)

Define viscosity, surface tension, and capillary rise o

Viscosity: the state of being thick, sticky, and semifluid in consistency, due to internal friction

o

Surface tension: the tension of the surface film of a liquid caused by the attraction of the particles in the surface layer by the bulk of the liquid, which tends to minimize surface area

o

Capillary rise: Capillary action is the ability of a liquid to flow in narrow spaces without the assistance of, or even in opposition to, external forces like gravity



Describe the roles of intermolecular attractive forces in each of these properties/phenomena o

Viscosity: the stronger the IMF, the higher the viscosity.

o

Surface tension: the stronger the IMF, the stronger the surface tension

o

Capillary rise: occurs when the intermolecular forces in the liquid are weaker than the adhesive forces with the outside substance.

Lecture 2: Part 1: Phase Transitions 

Define phase transitions and phase transition temperatures o

Phase transitions: describe transitions between solid, liquid, and gaseous states of matter 

During a phase transition of a given medium, certain properties of the medium change, often discontinuously, as a result of the change of external conditions, such as temperature, pressure, or others.

o

Phase transition temperatures: the temperature required to induce a phase transition in a certain substance.



Explain the relation between phase transition temperatures and intermolecular attractive forces o

The stronger the IMF, the higher the phase transition temperatures will be.

Part 2: Phase Diagrams •

Explain the construction and use of a typical phase diagram

o

Phase diagrams consist of the following 

Triple point: the point on a phase diagram at which the three states of matter: gas, liquid, and solid coexist



Critical point: the point on a phase diagram at which the substance is indistinguishable between liquid and gaseous states



Fusion(melting) (or freezing) curve: the curve on a phase diagram which represents the transition between liquid and solid states



Vaporization (or condensation) curve: the curve on a phase diagram which represents the transition between gaseous and liquid states



Sublimation (or deposition) curve: the curve on a phase diagram which represents the transition between gaseous and solid states

o

The use of a phase diagram is to be able to distinguish which phase a certain substance will be at a certain temperature and pressure. This allows for the further determination of the properties of the substance in the phase determined.



Use phase diagrams to identify stable phases at given temperatures and pressures, and to describe phase transitions resulting from changes in these properties o

Use the phase diagram to identify the physical state of a sample of water under specified conditions of pressure and temperature 

For example, using the diagram below, a pressure of 50 kPa and a temperature of −10 °C correspond to the region of the diagram labeled “ice.” Under these conditions, water exists only as a solid (ice). A pressure of 50 kPa and a temperature of 50 °C correspond to the “water” region—here, water exists only as a liquid.

 •

Describe the supercritical fluid phase of matter o

Supercritical fluid phase: any substance at a temperature and pressure above its critical point, where distinct liquid and gas phases do not exist.

o

Behavior of supercritical fluid phase: A supercritical fluid is any substance at a temperature and pressure above its critical point, where distinct liquid and gas phases do not exist. It can effuse through solids like a gas, and dissolve materials like a liquid. Small changes in pressure or temperature result in large changes in density, allowing many properties of a supercritical fluid to be dependent on these changes.

Lecture 3: Part 1: Solid State of Matter •

Define and describe the bonding and properties of ionic, molecular, metallic, and covalent network crystalline solids o

o

Ionic 

Bonding: ionic, bonds are electrostatic



Properties: high melting point, brittle, hard

Molecular 

Bonding: hydrogen bonding, dipole-dipole, London Dispersion forces

 o

Properties: low melting point, nonconducting

Metallic 

Bonding: metallic bonding



Properties: Variable hardness and melting point (depending upon strength of metallic bonding), conducting

o



Covalent network 

Bonding: covalent bonding



Properties: high melting point, hard, nonconducting

Describe the main types of crystalline solids: ionic solids, metallic solids, covalent network solids, and molecular solids 

Ionic solids: 

Consists of positively and negatively charged ions held together by electrostatic forces.



The strength of the attractive forces depends on the charge and size of the ions that compose the lattice and determines many of the physical properties of the crystal.



Lattice energy: the energy required to separate 1 mole of a crystalline ionic solid into its component ions in the gas phase



Metallic solids 

The valence electrons are no longer exclusively associated with a single atom, instead these electrons exist in molecular orbitals that are delocalized over many atoms, producing an electronic band structure.



Essentially, the metallic crystal consists of a set of metal cations in a sea of electrons.



Covalent network solids 

Formed by networks or chains of atoms or molecules held together by covalent bonds

 

A crystal of a covalent solid is one single large molecule

Molecular solids 

Consist of atoms or molecules held to each other by dipole–dipole interactions, London dispersion forces, or hydrogen bonds, or any combination of these



The intermolecular interactions in a molecular solid are relatively weak compared with ionic and covalent bonds, so molecular solids tend to be soft, low melting, and easily vaporized



Explain the ways in which crystal defects can occur in a solid o

Crystal defects are imperfections in the geometrical shape of atoms within a crystalline solid

o

These defects occur through deformation of the solid which can be caused from the rapid cooling from a high temperature or high energy radiation striking the solid

o

These defects can have significant effects on the mechanical, electrical, or optical behavior

Part 2: Lattice Structures •



Describe the arrangement of atoms and ions in crystalline structures o

Ions and atoms in a crystal lattice structure are bound by electrostatic attraction

o

The exact arrangement of ions in a crystal depends on the size of the ions in the crystal

Compute ionic radii using unit cell dimensions

o

The relationships between edge length and radius are as follows (for simple cubic cell, body center cubic cell, and face center cubic cell):



o

Use given cell dimensions to find edge length (a), and then use the above formulas in order to determine the radius (r)



Explain the use of X-ray diffraction measurements in determining crystalline structures o

X-ray diffraction is used for phase identification of a crystalline material and can provide information on unit cell dimensions

o

The instrument used accelerates electrons towards the sample, and when the electrons are strong enough to dislodge inner shell electrons of the sample, an x-ray spectrum is produced, allowing for the visualization of the structure of the sample

Lecture 4: Part 1: The Dissolution Process •

Describe the basic properties of solutions and how they form o

Solutions form by solvation: the breaking apart of a solute in a solvent to form a homogenous solution



Solvent particles surround the solute particles



The solvation process is thermodynamically favorable through the increase in entropy and the exothermic decrease in energy

o



Properties 

Rate of solubility: greater solubility = faster solvation



Concentration: larger ratio of solute to solvent = higher concentration

Predict whether a given mixture will yield a solution based on molecular properties of its components o

Solubility: the maximum amount of a solute that dissolved in a solvent at a given temperature



o

A higher temperature will allow higher solubility

o

Stirring solution will increase solubility

o

Smaller particle size will increase solubility (higher surface area of solute)

Explain why some solutions either produce or absorb heat when they form o

Due to the endothermic or exothermic nature of the chemical reaction (heat of solution) which is due to the intermolecular forces

o

Heat of solution is the sum of the enthalpy changes in the separation of solute molecules, separation of solvent molecules, and the formation of solute-solvent interactions

Part 2: Electrolytes •

Define and give examples of electrolytes o

Electrolytes: substances that are capable of carrying electric current when placed in water

o

Strong electrolytes: completely dissociate into ions in solution (NaCl)



o

Weak electrolytes: produce a few ions and do not dissociate fully (HF)

o

Nonelectrolytes: do not produce ions, but dissolve in water due to polarity (sugar)

Distinguish between the physical and chemical changes that accompany dissolution of ionic and covalent electrolytes o

Ionic: completely dissociated into its ions

o

Covalent: dipole-dipole interactions between the molecule with water rather than the ions with water



Relate electrolyte strength to solute-solvent attractive forces o

The stronger the electrolyte, the stronger the solute-solvent attractive forces

o

This is due to the ability to overcome the intermolecular forces within the molecule and to completely dissociate the molecule into its ions

Part 3: Solubility •

Describe the effects of temperature and pressure on solubility o

Temperature 

Higher temperature increases solubility for solids and liquids (in most cases)



Lower temperature increase solubility for gases and some exothermic reactions 

o

Pressure 

o

Keep gas in the solution instead of evaporating away

Higher pressure increases solubility for gases

Why? 

Increases the amount of solute/solvent collisions and increases speed/energy of particles (for solids and liquids



State Henry’s law and use it in calculations involving the solubility of a gas in a liquid

o

Henry’s Law: the solubility of a gas in a liquid is proportional to the pressure of the gas over the solution

o

c=kP 

c: concentration in molarity



k: constant that depends on the temperature (different value for different temperature), units: mol/L*atm

 •

P: pressure outside of the solution

Explain the degrees of solubility possible for liquid-liquid solutions o

Immiscible: two liquids that do not have any possible intermolecular forces with one another; will not mix or dissolve at all 

o

Nonpolar liquids are immiscible in water

Miscible: two liquids which share intermolecular forces and are able to dissolve or mix with one another 

Polar liquids or substances that form hydrogen bonds are miscible in water

Lecture 5: Part 1: Colligative Properties •

Express concentrations of solution components using mole fraction and molality o

Mole fraction 

The number of moles of a single solute divided by the total moles of all solutes/solvents

o



Mole fraction Xi= moles of i/moles of total solution



All mole fractions of individual solutes should total to 1

Molality 

Calculated by taking the moles of solute and dividing by the kilograms of solvent



Designated by a lower case m



m= moles of solute/ kg of solvent



Useful when temperature changes are considered and reports true concentration independent on temperature 

Temperature therefore changes the volume of solutions where masses are not affected by temperature

Part 2: Units of Concentration (Mole Fraction, Molarity, and Molality) 

Mole fraction o

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