Math SBA - math sba csec PDF

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math sba csec...

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Section 01 PROJECT TITLE

 An investigation to determine the maximum area of a vegetable garden that can be constructed from

Section 02 INTRODUCTION

TABLE OF CONTENTS 1. 2. 3. 4. 5. 6. 7. 8.

Title…………………………………………………………………………………..Page Number Introduction……………………………………………………………………...Page Number Method of Data Collection………………………………………………..Page Number Presentation of Data…………………………………………………………Page Number Analysis of Data………………………………………………………………..Page Number Discussion of Findings……………………………………………………….Page Number Conclusion………………………………………………………………………..Page Number References………………………………………………………………………..Page Number

9. Appendix…………………………………………………………………………..Page Number To d at th I am

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Section 03 Method of Data Collection

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On a sunny day, I went to the back side of my house with my measuring tape to capture the fields/plots precise perimeter/dimensions of available land. We also measured for a 1 meter foot path. The land had a rectangular shape, so I had measured the length and width as precise as possible. I had also measured the length of the wire.

Pictures were also taken of this plot of land.

Section 04 Presentation of Data

The data collected showed that: 1. The length of the full field is exactly 26.28 meters. 2. The width of the full field is approximately 11.88 meters. 3. The area of the full field is (26.28 x 11.88) = 312.20 m2

4. The foot path that would be implemented into the field is 1.02 meters there we take away this from both the full length and full width, giving us the 1 meter footpath and the final garden plot (26.28 - 1.02 x 2) and (11.88 – 1.02 x 2) = Length is 24.23 meters and the width is 9.83 meters.

5. The length of the wire is 77 meters.

Diagram is not drawn to scale.

Y Meters

1 meter footpath

X Meters

Vegetable Garden

X Meters

Y Meters The Diagram above is a model of the field the land/field to be fenced with 76 meters of wire; it also shows the plot and the 1 meter footpath.

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Let the length of the plot of the land to be fenced be Y meters.

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Let the width of the plot of the land to be fenced be X meters. Length of the wire to enclose the plot is 76 meters.  2x + 2y = 76  (2 x 11.88) + (2 x 26.28) = 76

Once again since there is a 1 meter foot path; the -

Width of the garden = (x – 2) meters Length of the garden = (y – 2) meters

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Width = (11.88 – 2) = 9.83 meters Length = (26.28 – 2) = 24.23 meters

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Area of the full field 

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26.28 x 11.88 = 312 m2

Area of field after including foot path  9.83 x 24.23 = 238 m2...