Resumen-algebra 1 - tatata tata tatata tatatatata tata tatata tatatatata tata tatata tatatatata PDF

Title Resumen-algebra 1 - tatata tata tatata tatatatata tata tatata tatatatata tata tatata tatatatata
Author Amand Victoriano Cauchy Fernandez
Course Algebra Lineal
Institution Universidade de Vigo
Pages 3
File Size 410.4 KB
File Type PDF
Total Downloads 19
Total Views 167

Summary

tatata tata tatata tatatatata tata tatata tatatatata tata tatata tatatatata tata tatata tatatatata tata tatata tata...


Description

· ij

ij

mxn

1xn mx1

A =

n

(aij )ni·j=1 Pndiag (A) = (a11 , a22, ..., ann ) tr (A) = i=1 aii = a11 + a22 + ... + ann (a12, a2,3 , ..., an−1,n )

(a21, a3,2 , ..., an,n−1 )

At ∈ Mnxm(R)

A ∈ Mmxn (R)



t



t

A ∈ Mmxn (C) ∗ = a aij ji

A∗ ∈ Mnxm(C) a+ib = a−bi

A∗ = A

diag(d1 , d2 , ...dn )

n

mxn

[A + B ]ij = aij + bij λ

λ

[λA]ij = λaij

A, B, C ∈ Mmxn (R)

α, β ∈ (K)

(A + B) + C = A + (B + C) A+B =B +A A+0=A=0+A A + (−A) = 0 = −A + A

α(A + B) = αA + αB (α + β)A = αA + βA (αβ )A = α(βA) ∈ Mmxn (K)

[(A + B) + C]ij = [A + B]ij + cij = aij + bij + cij = aij + [B + C]ij = [A + (B + C )]ij [A + B ]ij = aij + bij = bij + aij = [B + A]ij [A + 0]ij = aij + 0 = aij = 0 + aij = [0 + A]ij [A + (−A)]ij = aij − aij = 0 = (−aij ) + aij = [−A + A]ij [α(A + B)]ij = α[A + B ]ij = α(aij + bij ) = αaij + αbij = [αA]ij + [αB ]ij = [αA + βB]ij [(α + β)A]ij = (α + β)aij = αaij + βaij = [αA]ij + [βA]ij = [αA + βA]ij [(αβ)A]ij = (αβ)aij = α(βaij ) = α[βA]ij = [α(βA)]ij [1A]ij = 1aij = aij = [A]ij



 [AB ]ij = ai1 ai2

 b1j n  X   b2j  aik bkj . . . ain   = ai1 b1j + ai2 b2j + . . . + ain bnj =   k=1 bnj

A ∈ Mmxn (K), B

C ∈ Mnxp(R)

D ∈ Mpxq (R), α ∈ (R)

(AB)D = A(BD) AIn = A A = AIm α(AB ) = (αA)B = A(αB )

Pn Pn Pn Pn Pn Pn Pn [(AB)D] = a b d = [ AB ] d j = ( a b )d j = ij ih hk kj ik k ih hk k k=1 aih bhk dkj = h=1 k=1 h=1 k=1 h=1 k=1 Pn Pn Pn (b d ) = a a [ BD ] = [A ( BD )] hk kj ih ih hj ij k=1 h=1 h=1 [AIn ]ij =

Pn

k=1

aik [In ]kj = aij

[In ]jj = 1

[In ]kj = 0

k 6= j

Pn P P [α(AB)]ij = α[AB ]ij = α( k=1 aik bkj ) = nk=1 αaik bkj = nk=1(αA)ik bkj = [(αA)B]ij Pn Pn Pn Pn [A(B + C)]ij = k=1 a k(B + C) = a (b + c ) = a b + a c = i kj ik kj kj ik kj ik kj k=1 aik bkj + k=1 k=1 Pn h=1 aih chj = [AB]ij + [AC]ij = [AB + AC]ij...


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