Cap 2 termino algebraico y polinomios PDF

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Termino algebraico y polinomios, ejercicios resueltos y ejercicios para resolver....

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T1 = axm yn T2 = bxp yq m=p n=q

5x4 y−5 + 8x4 y−5 − 2x4 y−5 = 11x4 y−5

5 x3 16x2 y6

5x√−3 2 16x 2 y 3

P (x) = 3x2 − 5x + 6 P (−2) = 3(−2)2 − 5(−2)+6 =

28

M (x, y) = 2x2 y + M (1, −3) = 5xy − y 2(1)2 (−3) + 5(1)(−3)2 − (−3)3 2

16x2 y6

GR(x) = 2 GR(y) = 6

16x2 y6

axm yn + bxp yq = cxr ys a+b=c m=p=r n=q=s

3

ax2 + bx2 = 7x2

mxn + pxn = 10x3

−7w3 z 2 + mw3 z 2 = 3w3 z 2

(a + 1)x3a−1 + bx2b−3 = (c − 2)11 E=

√ a+b+c

12

t1 = 3xa+4yb+3 z c+2

A=

a+b+c 3

t2 = 2xb+4yc+3 z 8

p

n−2

(15n + 13)x17−n + (8n − 3)x4n−8

5x4

P (x, y) = 5x6+ayb+3a

2b 10

−8x y

Q(x, y)

=

P (x, y) = 5x y 3b2 − a 8 3a−b

−8x2a+b y7 ; Q(x, y)

=

2b = 6 + a 10 = 3a + b a = 2b − 6⇒ 10 = 3(2b − 6) + b ⇒ b = 4 ⇒a = 2

p

2n−3

(9n + 3)x4n−6 + (12n − 2)x3n−3

p(x) =

√ 2kx3k−3 + 3kx2k+2

∴4n − 6 = 3n − 3 ⇒ n = 3 p = 2(3)−3 (9 · 3 + 3)x4n−6 + (12 · 3 − 2)x3(3)−3 √ 3 = 64x6 = 4x2 4x2 E

=

5x6 q

8b+a a+1

6X a+b Y 4 − 2X 6 Y a = aX 6 Y b+2 4=a=b+2⇒a=4 b=2 q q √ 20 = = 4=2 E = 8·2+4 4+1 5

cx

b−6

= 4x

c+1

c 2a−2 + √ 3x E = a+b+c

N (x, y) =

E=

q 3

xa+b y 6b−3 x2 y 3b

(a + 2)x2a−3 y3b + (b − 5)xa+5y2a+b+8

√ 3 3a + 2b

7 P (x, y) = x2m+n−4 ym+n+2 + x2m+n−3 ym+n+1 + x2m+n−2 ym+n

P (x, y) = 7xa+3yb−2 z 6−a + 5xa+2 yb−3 z a+b

535

P (x) =

x x+1

P (P (m))

x

10

P (x, y) = x

2m−7 2m+3

y

− 5x

2m+6 m−9

y

3x

a−3

y

8x3 ya −

√ 3 8

4m − 4 = 56 =⇒ m = 15

P (x) =

x+3 x−1

P (0) = −3 P (3) = 3⇒ 4(−3 − 3) = −24

P [R(2)] = 80 P [9] = 80 45 + a = 80 ⇒ a = 35

S(x) =

x+2 x−2

5(S(3) − S(−3))

√ E = 3a + 2b + 2c

(a + 5)x3a−4 + bx4b−12 = (c + 7)x32

√ 8

x18 y 16

q 4

x2 y

√

x6 y 6

P (x, y) = x2m+n−4 ym+n+2 + x2m+n−3 ym+n+1 + x

2m+n−2 m+n

y...