Práctica #8 Ley De Hooke. Lab de mecanica clasica PDF

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LABORATORIO DE MECANICA CLASICAPRACTICA 8“Ley de Hooke”ALUMNA:MARTINEZ RODRIGUEZ KARLAPROFESORA:GONZALEZ SANDOVAL ADELAFECHA: 03 -Nov-INSTITUTO POLITECNICO NACIONALESCUELA SUPERIOR DE INGENIERIA QUIMICA EINDUSTRIAS EXTRACTIVASLEY DE HOOOKE####### 0 0 0 0 0####### 0 0 0 13 0. 000653####### 0 0 0 13 0...

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INSTITUTO POLITECNICO NACIONAL ESCUELA SUPERIOR DE INGENIERIA QUIMICA E INDUSTRIAS EXTRACTIVAS

LABORATORIO DE MECANICA CLASICA

PRACTICA 8 “Ley de Hooke”

ALUMNA: MARTINEZ RODRIGUEZ KARLA

PROFESORA: GONZALEZ SANDOVAL ADELA

FECHA:03-Nov-2021

LEY DE HOOOKE

0

0

0

0.02

0.01

0.196

19.6

0.00098

0.04 0.06

0.02 0.03

0.392 0.588

19.6 19.6

0.000932 0.00882

0.08 0.1

0.04 0.05

0.784 0.98

19.6 19.6

0.01568 0.0245

19.6

0.0509

𝐹1 = (0𝐾𝑔) (9.8 𝐹2 = (0.02) (9.8

𝑚 ) 𝑠2

𝐹3 = (0.04) (9.8

𝑚 ) 𝑠2

𝐹4 = (0.06) (9.8

𝑚 ) 𝑠2

0

0

𝑚 ) = 0𝑁 𝑠2

= 0.196𝑁

= 0.392𝑁

= 0.588𝑁 𝑚 𝐹5 = (0.08) (9.8 2 ) = 0.784𝑁 𝑠 𝑚 𝐹6 = (0.1) (9.8 𝑠2 ) = 0.98𝑁

𝐹 𝑥 0 0= =0 0 0.196 0.02 = = 19.6𝑁/𝑚 0.01 0.392 0.04 = 0.02 = 19.6N/m 0.588 0.06 = = 19.6𝑁/𝑚 0.03 0.784 0.08 = 0.04 = 19.6N/m 0.98 = 19.6𝑁/𝑚 0.1 = 0.05 𝐾=

𝑘𝑝𝑟𝑜𝑚 =

0 + 19.6 + 19.6 + 19.6 + 19.6 + 19.6 + 19.6 = 19.6 6

1 𝑊0 = (19.6)(02 ) = 0 2 1 𝑊0.02 = (19.6)(0.012 ) = 0.00098𝐽 2 1 𝑊0.04 = (19.6)(0.022 ) = 0.000932𝐽 2 1 𝑊0.06 = 2 (19.6)(0.032 ) = 0.00882J 1

𝑊0.08 = 2 (19.6)(0.042 ) = 0.01568J 1 𝑊0.1 = (19.6)(0.052 ) = 0.0245𝐽 2

0

0

0

0

0.02

0.015

0.196

13.06

0.04 0.06

0.03 0.045

0.392 0.588

13.06 13.06

0.002612 0.005877

0.08 0.1

0.06 0.075

0.784 0.98

13.06 13.06

0.010448 0.0163

13.06

𝐹1 = (0𝐾𝑔) (9.8 𝐹2 = (0.02) (9.8

𝑚 ) 𝑠2

= 0.392𝑁

𝐹4 = (0.06) (9.8

𝑚 ) 𝑠2

= 0.588𝑁

𝐹6 = (0.1) (9.8 𝐹 𝑥 0 0= =0 0 0.196 0.02 = = 13.06𝑁/𝑚 0.015

𝑠2

𝑚 ) 𝑠2

0.03589

= 0.196𝑁

𝑚 ) 𝑠2

𝐹5 = (0.08) (9.8

0.000653

𝑚 ) = 0𝑁 𝑠2

𝐹3 = (0.04) (9.8

𝑚

0

) = 0.784𝑁 = 0.98𝑁

𝐾=

0.04 =

0.392 0.03

0.08 =

0.784

0.1 =

0.06

0.075

0 + 13.06 + 13.06 + 13.06 + 13.06 + 13.06 = 13.06 6

= 13.06N/m

0.588 = 13.06𝑁/𝑚 0.06 = 0.045 0.98

𝑘𝑝𝑟𝑜𝑚 =

= 13.06N/m

= 13.06𝑁/𝑚

1 𝑊0 = (13.06)(02 ) = 0 2 1 𝑊0.02 = (13.06)(0.012 ) = 0.000653𝐽 2 1 𝑊0.04 = (13.06)(0.022 ) = 0.002612𝐽 2 1 𝑊0.06 = (13.06)(0.032 ) = 0.005877𝐽 2 1 𝑊0.08 = (13.06)(0.042 ) = 0.010448𝐽 2 1 𝑊0.1 = (13.06)(0.052 ) = 0.0163𝐽 2

0

0

0

0

0.02

0.005

0.196

39.2

0.00196

0.04 0.06

0.01 0.015

0.392 0.588

39.2 39.2

0.00784 0.01764

0.08 0.1

0.02 0.025

0.784 0.98

39.2 39.2

0.03136 0.049

39.2

𝐹1 = (0𝐾𝑔) (9.8 𝐹2 = (0.02) (9.8

= 0.196𝑁

𝑚 ) 𝑠2

= 0.392𝑁

𝐹4 = (0.06) (9.8

𝑚 ) 𝑠2

= 0.588𝑁

𝐹6 = (0.1) (9.8

𝑚

𝑠2

𝑚 ) 𝑠2

0.1078

𝑚 ) = 0𝑁 𝑠2

𝐹3 = (0.04) (9.8

𝐹5 = (0.08) (9.8

𝐹 𝑥 0 0= =0 0

𝑚 ) 𝑠2

0

) = 0.784𝑁 = 0.98𝑁

𝐾=

0.196 = 39.2𝑁/𝑚 0.005 0.392 0.04 = 0.01 = 39.2N/m 0.588 = 39.2𝑁/𝑚 0.06 = 0.015 0.784 0.08 = = 39.2N/m 0.02 0.98 = 39.2𝑁/𝑚 0.1 = 0.025 0.02 =

𝑘𝑝𝑟𝑜𝑚 =

0 + 39.2 + 39.2 + 39.2 + 39.2 + 39.2 = 39.2 6

1 𝑊0 = (39.2)(02 ) = 0 2 1 𝑊0.02 = (39.2)(0.012 ) = 0.00196𝐽 2 1 𝑊0.04 = (39.2)(0.022 ) = 0.00784𝐽 2 1 𝑊0.06 = (39.2)(0.032 ) = 0.01764𝐽 2 1 𝑊0.08 = (39.2)(0.042 ) = 0.03136𝐽 2 1 𝑊0.1 = (13.06)(0.052 ) = 0.049𝐽 2

1.2 1

FUERZA (N)

0.8 0.6

0.4 0.2 0 0

0.02

0.04

0.06

0.08

LONGITUD (m)

Wgraf=

(0.1𝑚)(1𝑁) 2

= 0.05J

P1(0,0) P2(0.05, 0.98) 0.98 − 0 = 19.6 𝑁/𝑚 𝐾𝑔𝑟𝑎𝑓 = 𝑚 = 0.05 − 0

0.0509J

19.6 N/m

0.05J

19.6 N/m

-0.01% 𝐸% =

0.05−0.0509 0.0509

𝐸% =

19.6 − 19.6 = 0% 19.6

= −0.01%

0%

0.1

0.12

1.2 1

FUERZA (N)

0.8 0.6 0.4 0.2 0 0

0.01

0.02

0.03

0.04

0.05

0.06

0.07

LONGITUD (m)

Wgraf=

(0.075𝑚)(0.98𝑁) 2

= 0.03675J

P1(0,0) P2(0.075, 0.98) 0.98 − 0 𝐾𝑔𝑟𝑎𝑓 = 𝑚 = = 13.06 𝑁/𝑚 0.075 − 0

0.03589J

13.06 N/m

0.03675J

13.06 N/m

0.02%

𝐸% = 𝐸% =

0.03675−0.03589 0.03589

13.06 − 13.06 13.06

= 0.02%

= 0%

0%

0.08

0.09

1.2 1

FURZA (N)

0.8 0.6 0.4 0.2

0 0

0.005

0.01

0.015

0.02

LONGITUD (m)

Wgraf=

(0.025𝑚)(0.98𝑁) 2

= 0.01225

P1(0,0) P2(0.025, 0.98) 0.98 − 0 = 39.2 𝑁/𝑚 𝐾𝑔𝑟𝑎𝑓 = 𝑚 = 0.025 − 0

0.1078J

39.2 N/m

0.01225J

39.2 N/m

-0.01%

𝐸% = 𝐸% =

0.01225−0.1078 0.1078

39.2 − 39.2 = 0% 39.2

= −0.88%

0%

0.025

0.03

CONCLUSIÓN Los cálculos de esta practica fueron casi perfectos, pues los cálculos del trabajo y de la constante de recuperación variaron solo por milésimas en los cálculos teóricos y los datos experimentales, en las graficas pudimos observar tanto la fuerza como la constante y se formo una pendiente que gracias a esto se concluye que los cuerpos producen aceleraciones y deformaciones sobre los cuerpos elásticos donde existe una relación directamente proporcional las magnitudes que son la constante de elasticidad del resorte, el alargamiento del resorte y la fuerza aplicada....