Title | Formulario Calculo Integral |
---|---|
Course | Calculo |
Institution | Universidad Mayor de San Simón |
Pages | 2 |
File Size | 136.1 KB |
File Type | |
Total Downloads | 51 |
Total Views | 128 |
Lo necesario para entender y aclarar algunas dudas que puedas tener espero te sirva....
𝑏
CALCULO INTEGRAL
∫ 𝑓(𝑥) = − ∫ 𝑓(𝑥)𝑑𝑥
Trigonometría sin 𝜃 =
𝐶𝑂 ; 𝐻𝐼𝑃
csc 𝜃 =
𝐶𝐴 cos 𝜃 = ; 𝐻𝐼𝑃
1 sin 𝜃
1 sec 𝜃 = cos 𝜃
sin 𝜃 𝐶𝑂 tan 𝜃 = ; = cos 𝜃 𝐶𝐴
1 cot 𝜃 = tan 𝜃
𝑠𝑖𝑛 𝜃 + 𝑐𝑜𝑠 𝜃 = 1 2
2
𝑡𝑎𝑛2 𝜃 + 1 = 𝑠𝑒𝑐 2 𝜃
𝑐𝑜𝑠 2 𝜃 = 𝑡𝑎𝑛2 𝜃 =
1 − cos 2𝜃 1 + cos 2𝜃 𝑏
𝑏
∫{𝑓(𝑥) ± 𝑔(𝑥)}𝑑𝑥= ∫ 𝑓(𝑥)𝑑𝑥 ± ∫ 𝑔(𝑥)𝑑𝑥 𝑏
𝑎
𝑎
𝑏
𝑐
𝑎
𝑏
∫ 𝑓 (𝑥)𝑑𝑥 =∫ 𝑓(𝑥)𝑑𝑥 + ∫ 𝑓(𝑥)𝑑𝑥 𝑎
𝑎
Integrales
∫
𝑢𝑛+1 , 𝑛+1
𝑑𝑢 = ln|𝑢| 𝑢
𝑐
∫ 𝑢𝑎𝑢 𝑑𝑢 =
𝑎𝑢 1 ) (𝑢 − 𝐼𝑛 𝑎 𝐼𝑛 𝑎
∫ 𝑢𝑒 𝑢 𝑑𝑢 = 𝑒 𝑢 (𝑢 − 1)
∫ ln(𝑢)𝑑𝑢 = 𝑢 ln(𝑢) − 𝑢 ∫ 𝑙𝑜𝑔𝑎 𝑢𝑑𝑢 =
∫ 𝑎𝑑𝑥 = 𝑎𝑥
𝑛 ≠ −1
Integrales funciones log. y exp .
∫ 𝑒 𝑢 𝑑𝑢 = 𝑒 𝑢
∫ 𝑐𝑓(𝑥)𝑑𝑥 =𝑐 ∫ 𝑓(𝑥)𝑑𝑥
𝑎
𝑎
∫ 𝑢𝑛 𝑑𝑢 =
Integrales definidas, propiedades
𝑏
𝑚(𝑏 − 𝑎) ≤ ∫ 𝑓(𝑥)𝑑𝑥≤ 𝑀(𝑏 − 𝑎)
∫ 𝑢𝑑𝑣 = 𝑢𝑣 − ∫ 𝑣𝑑𝑢
1 + cos 2𝜃 2
𝑎
𝑏
∫(𝑢 ± 𝑣 ± ⋯ )𝑑𝑥 = ∫ 𝑢𝑑𝑥 ± ∫ 𝑣𝑑𝑥 ± …
1 − cos 2𝜃 2
𝑏
𝑏
𝑎
∫ 𝑎𝑓(𝑥)𝑑𝑥 = 𝑎 ∫ 𝑓(𝑥)𝑑𝑥
1 + 𝑐𝑜𝑡 2 𝜃 = 𝑐𝑠𝑐 2 𝜃
𝑠𝑖𝑛2 𝜃 =
𝑎
𝑎𝑢 𝑎 > 0 ∫ 𝑎𝑢 𝑑𝑢 = { 𝐼𝑛 𝑎 𝑎 ≠ 1
1 (𝑢 ln(𝑢) − 𝑢) ln 𝑎
∫ 𝑢𝑙𝑜𝑔𝑎 𝑢𝑑𝑢 =
∫ 𝑢 ln(𝑢)𝑑𝑢 =
𝑢2 (2𝑙𝑜𝑔𝑎 𝑢 − 1) 4 𝑢2 (2 ln(𝑢) − 1) 4
Integrales de funciones trig.
∫ sin(𝑢) 𝑑𝑢 = −cos (𝑢) ∫ cos(𝑢) 𝑑𝑢 = 𝑠𝑒𝑛(𝑢) ∫ 𝑠𝑒𝑐 2 (𝑢)𝑑𝑢 = tan (𝑢) ∫ 𝑐𝑠𝑐 2 (𝑢)𝑑𝑢 = −cot (𝑢) ∫ sec(𝑢) tan(𝑢) 𝑑𝑢 = sec (𝑢) ∫ csc(𝑢) cot(𝑢) 𝑑𝑢 = − csc (𝑢)
∫ tan(𝑢) 𝑑𝑢 = − ln|cos 𝑢| = ln|sec 𝑢| ∫ cot(𝑢) 𝑑𝑢 = ln|𝑠𝑒𝑛 𝑢|
∫ csc −1 (𝑢) 𝑑𝑢
𝑢 1 ∫ 𝑠𝑒𝑛2 (𝑢)𝑑𝑢 = − 𝑠𝑒𝑛(2𝑢) 2 4
∫ 𝑡𝑎𝑛
2 (𝑢)𝑑𝑢
= 𝑢 csc −1 (𝑢 ) + 𝐼𝑛 (𝑢 + √𝑢 2 − 1)
𝑢 1 = + 𝑠𝑒𝑛(2𝑢) 2 4
𝑑𝑢 𝑢 1 ∫ 2 = tan−1 ( ) 𝑢 + 𝑎2 𝑎 𝑎
∫
∫ 𝑐𝑜𝑡 2 (𝑢)𝑑𝑢 = −(cot(𝑢) + 𝑢) ∫ 𝑢 𝑠𝑒𝑛 (𝑢) 𝑑𝑢 = 𝑠𝑒𝑛(𝑢) − 𝑢 cos(𝑢) ∫ 𝑢 𝑐𝑜𝑠 (𝑢) 𝑑𝑢 = 𝑐𝑜𝑠 (𝑢) + 𝑢 sen(𝑢) Integrales de funciones trigonométricas inversas
∫ sin−1 (𝑢) 𝑑𝑢 = 𝑢 sin−1 (𝑢) + √1 − 𝑢 2 ∫ cos −1 (𝑢) 𝑑𝑢
=
𝑢 cos −1 (𝑢)
− √1 −
𝑢2
𝑑𝑢 𝑢−𝑎 1 ln | = |, 𝑢 2 − 𝑎 2 2𝑎 𝑢 + 𝑎
𝑑𝑢 𝑎+𝑢 1 |, ∫ 2 = ln | 𝑎−𝑢 𝑎 − 𝑢 2 2𝑎
(𝑢 2 > 𝑎 2 ) (𝑢 2 < 𝑎 2 )
𝑢 = sin−1 ( ) ∫ 𝑎 √𝑎2 − 𝑢 2 √𝑢 2 ± 𝑎 2
= ln (𝑢 + √𝑢 2 ± 𝑎 2 )
1 𝑢 = ln ( ) ∫ 2 2 𝑎 𝑢√𝑎 ± 𝑢 𝑎 + √𝑎2 ± 𝑢 2 𝑑𝑢
𝑎 1 ∫ = cos−1 ( ) 𝑢 𝑢 √𝑢 2 − 𝑎 2 𝑎 𝑑𝑢
𝑛
𝑛
𝑘=1
𝑘=1
∑ 𝑐𝑎𝑘 = 𝑐 ∑ 𝑎𝑘
∑ 𝑐 = 𝑛𝑐 𝑘=0
𝑛
𝑛
𝑛
𝑘=1
𝑘=1
𝑛
∑(𝑎𝑘 + 𝑏𝑘 ) = ∑ 𝑎𝑘 + ∑ 𝑏𝑘 𝑛
𝑘=1
𝑛
𝑑𝑢
∫
√𝑎2 − 𝑢 2 +
𝑘=1
Integrales con raíz
𝑑𝑢
2
∑(𝑎𝑘 − 𝑎𝑘−1 ) = 𝑎𝑛 − 𝑎0
Integrales de fracciones
= tan(𝑢) − 𝑢
𝑢
𝑎2 𝑢) sin−1 ( 𝑎 2 𝑢 𝑎2 ln (𝑢 + √𝑢2 ± 𝑎2 ) ∫ √𝑢2 ± 𝑎 2 𝑑𝑢 = √𝑢2 ± 𝑎2 ± 2 2 ∫ √𝑎2 − 𝑢 2 𝑑𝑢 =
Sumatorias
= 𝑢 sec −1 (𝑢 ) − 𝐼𝑛 (𝑢 + √𝑢 2 − 1)
∫ csc(𝑢) 𝑑𝑢 = ln|csc 𝑢 − cot 𝑢 |
∫ 𝑐𝑜𝑠
∫ cot −1 (𝑢) 𝑑𝑢 = 𝑢 cot −1 (𝑢) + 𝐼𝑛 √1 + 𝑢 2 ∫ sec −1 (𝑢) 𝑑𝑢
∫ sec(𝑢) 𝑑𝑢 = ln|sec 𝑢 + tan 𝑢|
2 (𝑢)𝑑𝑢
∫ tan−1 (𝑢) 𝑑𝑢 = 𝑢 tan−1 (𝑢) − 𝐼𝑛 √1 + 𝑢 2
𝑛 𝑛 ∑[𝑎 + (𝑘 − 1)𝑑] = [2𝑎 + (𝑛 − 1)𝑑] = (𝑎 + 𝑙) 2 2 𝑘=1
𝑛
∑ 𝑎𝑟 𝑘−1 = 𝑎
𝑘=1 𝑛
1 − 𝑟 𝑛 𝑎 − 𝑟𝑙 = 1−𝑟 1−𝑟
1 ∑ 𝑘 = (𝑛2 + 𝑛) 2 𝑘=1 𝑛
1 ∑ 𝑘2 = (2𝑛3 + 3𝑛 2 + 𝑛) 6 𝑘=1 𝑛
1 ∑ 𝑘3 = (𝑛4 + 2𝑛 3 + 𝑛2 ) 4 𝑘=1 𝑛
∑ 𝑘4 = 𝑘=1
1 (6𝑛 5 + 15𝑛4 + 10𝑛3 − 𝑛) 30...